有一个list要存不想用数据库,有什么方案吗?
难道要这样存吗:
key="a1" value="xxxx"
key="a2" value="xxxx"
key="a3" value="xxxx"
key="a4" value="xxxx"
key="a5" value="xxxx"
key="a6" value="xxxx"
难道要这样存吗:
key="a1" value="xxxx"
key="a2" value="xxxx"
key="a3" value="xxxx"
key="a4" value="xxxx"
key="a5" value="xxxx"
key="a6" value="xxxx"
需要用到:commons-codec-1.4.jar AddNewWord addWord=new AddNewWord();
addWord.setWords(word.getWords());
addWord.setWordClass(i);
SharedPreferences mySharedPreferences=getSharedPreferences("new_word", Activity.MODE_WORLD_READABLE);
ByteArrayOutputStream baos = new ByteArrayOutputStream(3000);
ObjectOutputStream oos=null;
try {
oos = new ObjectOutputStream(baos);
oos.writeObject(addWord);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// 将Product对象放到OutputStream中
// 将Product对象转换成byte数组,并将其进行base64编码
String newWord = new String(Base64.encodeBase64(baos.toByteArray()));
SharedPreferences.Editor editor = mySharedPreferences.edit();
// 将编码后的字符串写到base64.xml文件中
editor.putString("newWord", newWord);
editor.commit();
读取对象:
String wordBase64 = mySharedPreferences.getString("new_word", "");
// 对Base64格式的字符串进行解码
byte[] base64Bytes = Base64.decodeBase64(wordBase64 .getBytes());
ByteArrayInputStream bais = new ByteArrayInputStream(base64Bytes);
ObjectInputStream ois = new ObjectInputStream(bais);
// 从ObjectInputStream中读取Product对象
AddNewWord addWord= (AddNewWord ) ois.readObject();
对象实体:
public class AddNewWord implements Serializable{ private static final long serialVersionUID = -37782648386953312L;
private String words;
private int wordClass;
public String getWords() {
return words;
}
public void setWords(String words) {
this.words = words;
}
public int getWordClass() {
return wordClass;
}
public void setWordClass(int wordClass) {
this.wordClass = wordClass;
}
@Override
public String toString() {
return "AddNewWord [words=" + words
+ ", wordClass=" + wordClass
+ "]";
}
}