android在界面点返回button用setContentView返回后原来设置失效怎么解决呢
public class Actjava extends Activity{
public void onCreate(Bundle savedInstanceState){
super onCreate(savedInstanceState);
setContentView(R.layout.main);
Button button = (Button)this.findViewById(R.layout.button1);
button,setOnClickListener(new OnClickListener{
@Override
public void onClick(View v){
setContentView(R.layout.**) //跳到另一个activity界面
}
}
);
}
}
setContentView(R.layout.**) 跳到另一个activity界面后,原来的内容就都失效了,怎么能既跳转,而且原来的内容不失效呢?
public class Actjava extends Activity{
public void onCreate(Bundle savedInstanceState){
super onCreate(savedInstanceState);
setContentView(R.layout.main);
Button button = (Button)this.findViewById(R.layout.button1);
button,setOnClickListener(new OnClickListener{
@Override
public void onClick(View v){
setContentView(R.layout.**) //跳到另一个activity界面
}
}
);
}
}
setContentView(R.layout.**) 跳到另一个activity界面后,原来的内容就都失效了,怎么能既跳转,而且原来的内容不失效呢?
it.putExtra("student", stus.get(arg2));
startActivity(it);记得需要在Mainfest.xml 申明StudentDescribeActivity
Intent intent=new Intent();
intent.setclass(a.this,b,class);
startActivity(intent);