receiver代码: public void onReceive(Context context, Intent intent) {
Log.e(TAG, "AlarmReceiver.onReceive");
// 关闭应用程序之后仍然可以调用service
dbID = intent.getIntExtra("dbID", 1991);
Log.e(TAG, "dbID="+dbID);
Intent myIntent = new Intent(context, AlarmService.class);
myIntent.putExtra("dbID", dbID);
context.startService(myIntent);
Log.e(TAG, "service started");
}receiver已经注册了,但是没有加intentfilter,不知道会不会影响,代码如下:
<receiver
android:name="org.liewwanpang.pills.broadcastreceiver.RepeatReceiver">
</receiver>情况是有时候能接收到,有时候却又不能,请高手指教!!!
Log.e(TAG, "AlarmReceiver.onReceive");
// 关闭应用程序之后仍然可以调用service
dbID = intent.getIntExtra("dbID", 1991);
Log.e(TAG, "dbID="+dbID);
Intent myIntent = new Intent(context, AlarmService.class);
myIntent.putExtra("dbID", dbID);
context.startService(myIntent);
Log.e(TAG, "service started");
}receiver已经注册了,但是没有加intentfilter,不知道会不会影响,代码如下:
<receiver
android:name="org.liewwanpang.pills.broadcastreceiver.RepeatReceiver">
</receiver>情况是有时候能接收到,有时候却又不能,请高手指教!!!
那action是怎么加上去啊?
android:name="org.liewwanpang.pills.broadcastreceiver.RepeatReceiver">
<intent-filter>
<action android:name="com.android.startreceiver"/>
</intent-filter>
</receiver>Activity中发送广播
Intent intent = new Intent();
intent.setAction("com.android.startreceiver");
sendBroadcast(intent);
是怎么弄的?setclassname?
理论上好像也行啊。