菜鸟求助

Question

解析出来的数据用list集合存放,list集合用map采用键值对存放，List<Map<String,String>

Answer 1

使用适配器绑定数据：参考：http://www.cnblogs.com/allin/archive/2010/05/11/1732200.html

Answer 2

for (int i = 0; i < jsonArray.length(); ++i) {
HashMap<String, Object> map = new HashMap<String, Object>();
JSONObject o = (JSONObject) jsonArray.get(i);
map.put("t_name", o.getString("t_name"));
map.put("t_phone",o.getString("t_phone"));
list.add(map);  
//System.out.println("id:" + o.getString("id") + ","
// + "t_name:" + o.getString("t_name") + "," 
// + "t_phone:"+ o.getString("t_phone") );
 
}
  
SimpleAdapter listAdapter = new SimpleAdapter(this,list, R.layout.user, new String[] {"t_name","t_phone"},   
                new int[] {R.id.t_name,R.id.t_phone});   
        //这是Adapter setListAdapter()此方法来自ListActivity   
        setListAdapter(listAdapter);