*********************请教一个xslt的问题**********************

Question

test.xml<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<deal>
<begin>  
<seat SeatNo="1" cards="1,2,3,4,5,6" />  
<seat SeatNo="2" cards="1,2,3,4,5,6" />  
<seat SeatNo="3" cards="1,2,3,4,5,6" />  
</begin>  
<players>  
<seat SeatNo="1" playerid="user01"/>  
<seat SeatNo="2" playerid="user02"/>  
<seat SeatNo="3" playerid="user03" />  
</players> 
</deal>test.xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">
  <xsl:template match="/">
    <xsl:for-each select="//begin/seat">
      <xsl:variable name="id" select="@SeatNo"/>
      Begin_SeatNo:<xsl:value-of select="$id"/> Player_playerID <xsl:value-of select="//players/seat[@SeatNo=$id]/@playerid"/><br/>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>结果
Begin_SeatNo:1 Player_playerID user01
Begin_SeatNo:2 Player_playerID user02
Begin_SeatNo:3 Player_playerID user03

Answer 1

或者test.xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">
  <xsl:template match="//begin/seat">
      <xsl:variable name="id" select="@SeatNo"/>
      Begin_SeatNo:<xsl:value-of select="$id"/> Player_playerID <xsl:value-of select="//players/seat[@SeatNo=$id]/@playerid"/><br/>
  </xsl:template>
</xsl:stylesheet>或者test.xsl<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">
  <xsl:template match="//begin/seat">
      Begin_SeatNo:<xsl:value-of select="@SeatNo"/> 
Player_playerID <xsl:call-template name="getName"><xsl:with-param name="id" select="@SeatNo"/></xsl:call-template><br/>
  </xsl:template>
<xsl:template name="getName">
<xsl:param name="id"/>
<xsl:value-of select="//players/seat[@SeatNo=$id]/@playerid"/>
</xsl:template>
</xsl:stylesheet>
写法很多，我不一一写了。