本帖最后由 stone1314 于 2013-11-09 16:18:22 编辑

解决方案 »

  1.   

    今天搞了一天的MVC,在显示图片的时候老是出现问题,从网上搜索了好久,才找到解决方法。首先是创建一个类,继承于ActionResult,记住要引用System.Web.Mvc命名空间,如下:public class ImageResult : ActionResult
        {
            public ImageFormat ContentType { get; set; }
            public Image image { get; set; }
            public string SourceName { get; set; }        public ImageResult(string _SourceName, ImageFormat _ContentType)
            {
                this.SourceName = _SourceName;
                this.ContentType = _ContentType;
            }        public ImageResult(Image _ImageBytes, ImageFormat _ContentType)
            {
                this.ContentType = _ContentType;
                this.image = _ImageBytes;
            }        public override void ExecuteResult(ControllerContext context)
            {
                context.HttpContext.Response.Clear();
                context.HttpContext.Response.Cache.SetCacheability(HttpCacheability.NoCache);
                if (ContentType.Equals(ImageFormat.Bmp)) context.HttpContext.Response.ContentType = "image/bmp";
                if (ContentType.Equals(ImageFormat.Gif)) context.HttpContext.Response.ContentType = "image/gif";
                if (ContentType.Equals(ImageFormat.Icon)) context.HttpContext.Response.ContentType = "image/vnd.microsoft.icon";
                if (ContentType.Equals(ImageFormat.Jpeg)) context.HttpContext.Response.ContentType = "image/jpeg";
                if (ContentType.Equals(ImageFormat.Png)) context.HttpContext.Response.ContentType = "image/png";
                if (ContentType.Equals(ImageFormat.Tiff)) context.HttpContext.Response.ContentType = "image/tiff";
                if (ContentType.Equals(ImageFormat.Wmf)) context.HttpContext.Response.ContentType = "image/wmf";
                if (image != null)
                {
                    image.Save(context.HttpContext.Response.OutputStream, ContentType);
                }
                else
                {
                    context.HttpContext.Response.TransmitFile(SourceName);
                }
            }
        }然后在 Controller类中创建一个Action.如下:public ActionResult GetPicture(int id)
            {         
                ICategory server = new CategoryServer();
                byte[] buffer = server.getCategoryPicture(id);
                if (buffer != null)
                {
                    MemoryStream stream = new MemoryStream(buffer);
                    System.Drawing.Image image = System.Drawing.Image.FromStream(stream);
                    ImageResult result = new ImageResult(image, System.Drawing.Imaging.ImageFormat.Jpeg);
                    return result;
                }
                return View();
            } 这样就可以显示图片了。 下面几种方法可以显示已经存在的图片 
     方法一: using System.IO;public FileResult Image() {
        string path = Server.MapPath("/Content/Images/Decorative/");
        string filename = Request.Url.Segments[Request.Url.Segments.Length - 1].ToString();    // Uss Path.Combine from System.IO instead of StringBuilder.
        string fullPath = Path.Combine(path, filename);    return(new FileResult(fullPath, "image/jpeg"));}
    方法二:
    public ActionResult Image(string id)
    {
        var dir = Server.MapPath("/Images");
        var path = Path.Combine(dir, id + ".jpg");
        return base.File(path, "image/jpg");
    }
    方法三:
    [AcceptVerbs(HttpVerbs.Get)]
    [OutputCache(CacheProfile = "CustomerImages")]
    public FileResult Show(int customerId, string imageName)
    {
        var path = string.Concat(ConfigData.ImagesDirectory, customerId, @"\", imageName);
        return new FileStreamResult(new FileStream(path, FileMode.Open), "image/jpeg");
    }
    这三种都可以显示已经存在的图片
    并且我认为第三种方法可以修改为从数据库中读取图片显示。