.net中如何取出xml中最后10条信息(也就是最新信息)

Question

.net中如何取出xml中最后10条信息(也就是最新信息)

Answer 1

<news>
<new id="1">
   <title>Test</title>
    <content>asdfsadfsadgsdagsdg</content>
    <time>2010-11-18 15:40:25</time>
  </new>
  <new id="2">
    <title>hhhhhh</title>
    <content>jjjjjjjjj</content>
    <time>2010-11-18 15:42:17</time>
  </new>
  <new id="3">
    <title>qqqqqq</title>
    <content>sssssssss</content>
    <time>2010-11-18 15:42:49</time>
  </new>
  <new id="4">
    <title>sssssssss</title>
    <content>ddddddddddd</content>
    <time>2010-11-18 15:46:30</time>
  </new>
  <new id="5">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="6">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="7">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="8">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="9">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="10">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
  <new id="11">
    <title>nihaoya</title>
    <content>ffffffff</content>
    <time>2010-11-18 15:50:37</time>
  </new>
</news>

Answer 2

xml
首先用lastchild取最后一条,即最新条
然后用当前节点的previousSibling取上一样,依次类推,直至满10条或者用childNodes集合
再用 for (var i=集合.length-1;i=0;i--)

Answer 3

LinqToXml如下，先按照时间进行排序，然后去前10个            XDocument xDoc = XDocument.Load("D:\\aa.xml");            var mySet = xDoc.Elements("new").OrderByDescending(x => DateTime.Parse(x.Element("time").Value))
                .Take(10)
                .Select(x => new {
                    title = x.Element("title").Value,
                    content = x.Element("content").Value,
                    time = x.Element("time").Value
                }).ToList();

Answer 4

上面的有点小bug，正确的如下            var mySet = xDoc.Element("news").Elements("new").OrderByDescending(x => DateTime.Parse(x.Element("time").Value))
                .Take(10)
                .Select(x => new {
                    title = x.Element("title").Value,
                    content = x.Element("content").Value,
                    time = x.Element("time").Value
                }).ToList();

Answer 5

不用linq，用document这种方式遍历，怎么弄？

Answer 6

 XmlDocument XmlDoc = new XmlDocument();            XmlNodeList list = XmlDoc.GetElementsByTagName("new");
  for (int i = list.Count; i > list.Count-10; i++)
        {
         }