c# 读取xml中 单个的节点的值

Question

<?xml version="1.0" encoding="utf-8" ?>
<shenhe>
    <shenhes>
        <value>1</value>
    </shenhes>
</shenhe>
c# 读取xml中 单个的节点的值  如上面所示  如何读到那个1
请大大们 给我写详细点 什么引用啊 注释啊  我很笨  大家费心

Answer 1

先引用using System.Xml;
XmlDocument xml = new XmlDocument();
xml.Load(@"d:\test.xml");
XmlNode node = xml.SelectSingleNode("/shenhe/shenhes/value");
Response.Write(node.InnerText);

Answer 2

xmldocument
 getelementBytag（“value”）.innertext

Answer 3

XmlDocument xmlDoc=new XmlDocument();
xmlDoc.Load(@"文件路径");
Xmlnode node=xmlDoc.SelectSingleNode(@"/shenhe/shenhes/value");
输出：node.InnerXml;开头using System.Xml;

Answer 4

将节点字段写成实体类。public void BindXml()
        {
            List<MarketProject.platform.modules.Information> list = new List<MarketProject.platform.modules.Information>();
            //实例化xml
            XmlDocument xml = new XmlDocument();
            //读取xml文件
            xml.Load(@"F:\\360data\\重要数据\\桌面\\Update_umis\\01.WebProject\\MarketProject\\et\\Test.xml");  //你的xml地址
            string id = "";
            string name = "";
            string sex = "";
            MarketProject.platform.modules.Information info = null;
            //////////*******下面开始循环读取xml文件信息********/
            ///////////////
            foreach (XmlNode node in xml.ChildNodes)
            {
                if (node.Name == "abc")
                {
                    foreach (XmlNode node1 in node.ChildNodes)
                    {
                        if (node1.Name == "item")
                        {
                            foreach (XmlNode node2 in node1.ChildNodes)
                            {
                                switch (node2.Name)
                                {
                                    case "id":
                                        id = node2.InnerText;
                                        break;
                                    case "name":
                                        name = node2.InnerText;
                                        break;
                                    default:
                                        sex = node2.InnerText;
                                        break;
                                }
                            }
                            info = new MarketProject.platform.modules.Information(id, name, sex);
                            //将信息保存至集合
                            list.Add(info);
                        }
                    }
                }
            }
            GridView1.DataSource = list;
            GridView1.DataBind();
        }

Answer 5

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;namespace MarketProject.platform.modules
{
    public class Information
    {
        private string id;
        public string Id
        {
            get { return id; }
            set { id = value; }
        }
        private string name;
        public string Name
        {
            get { return name; }
            set { name = value; }
        }
        private string sex;
        public string Sex
        {
            get { return sex; }
            set { sex = value; }
        }
        public Information()
        {        }
        public Information(string id, string name, string sex)
        {
            this.Id = id;
            this.Name = name;
            this.Sex = sex;
        }    }
}