C#窗体里ContextMenuStrip的问题

Question

    private void btnTab1_Click(object sender, EventArgs e)
        {
            
            if (MessageBox.Show("确定开启餐台吗？？", "提示", MessageBoxButtons.OKCancel, MessageBoxIcon.Information) == DialogResult.OK)
            {
                //你要做的事情
                Button b = new Button();
                b = (Button)sender;
                MessageBox.Show(b.Text);
                changeimage(b);
                OpenTab op = new OpenTab();
                op.Show();
            }
            else
            {            }
          
        }
//上面 我能的到桌号
 private void 餐台状态ToolStripMenuItem_Click(object sender, EventArgs e)
        {
            
            SeeTabLog stb = new SeeTabLog();
            stb.Show();
        }
//右击后 要传个值  然后打开相对应的 餐桌 不清楚怎么写！！

Answer 1

SeeTabLog stb = new SeeTabLog(桌号);
是这样吗，把参数传到打开的窗体里，窗体写个全局变量 = 桌号