C# 串口发送一组数据，然后接收一个BD，再发第二组，不知道哪里有错，收不了！

Question

                          ReDatCount = Receive();
                          if (ReDatCount == 7)
                            
                         comm.Read(readbuffer, 0, ReDatCount);
                     if (readbuffer[0] != 0xbd)
                         break;//子函数
        public int Receive()
        {
            int ReDatCount = 0;
            timeReceive.Interval = 500;
            timeReceive.Enabled = true;
            while (timeReceive.Enabled == true)
            {
                if (mycomm.BytesToRead > ReDatCount)
                {
                    ReDatCount = mycomm.BytesToRead;
                    timeReceive.Enabled = false;
                    timeReceive.Interval = 100;
                    timeReceive.Enabled = true;
                }
                else
                {
                    Application.DoEvents();
                }
            }
            return ReDatCount;
        }        private void timeReceive_Tick(object sender, EventArgs e)
        {
            timeReceive.Enabled = false;
        }

Answer 1

        private void timer_Tick(object sender, EventArgs e)
        {
            char[] sendbyte = { '#', 'R', 'P', '\r', '\n' };            cptComPort.Write(sendbyte, 0, sendbyte.Length);            if (cptComPort.BytesToRead > 0)
            {
                char[] receivebyte = new char[cptComPort.BytesToRead];
                cptComPort.Read(receivebyte, 0, receivebyte.Length);
                if ((receivebyte[0] == '#') && (receivebyte[1] == 'R') && (receivebyte[2] == 'P') && (receivebyte[13] == 'M') && (receivebyte[14] == 'P') && (receivebyte[15] == 'a'))
                {
                    char[] b = new char[10];
                    for (int i = 0; i < 10; i++)
                    {
                        b[i] = receivebyte[i + 3];
                    }
                    decComPress = decimal.Parse(new string(b));
                    /*decComPress = (decimal)((b[1] - 0x30) * 100 + (b[2] - 0x30) * 10 + (b[4] - 0x30) * 0.1 + (b[5] - 0x30) * 0.01 + (b[6] - 0x30) * 0.001 + (b[7] - 0x30) * 0.0001 + (b[8] - 0x30) * 0.00001 + (b[9] - 0x30) * 0.000001);
                    if (b[0] == '-')
                        decComPress = -decComPress;*/
                }
}我也是刚学，在定时器中断里面，发送一串字符，然后查询接收，看看对你有用不。

Answer 2

        private void timer_Tick(object sender, EventArgs e)
        {
            char[] sendbyte = { '#', 'R', 'P', '\r', '\n' };            cptComPort.Write(sendbyte, 0, sendbyte.Length);            //System.Threading.Thread.Sleep(100);            if (cptComPort.BytesToRead > 0)
            {
                char[] receivebyte = new char[cptComPort.BytesToRead];
                cptComPort.Read(receivebyte, 0, receivebyte.Length);
                if ((receivebyte[0] == '#') && (receivebyte[1] == 'R') && (receivebyte[2] == 'P') && (receivebyte[13] == 'M') && (receivebyte[14] == 'P') && (receivebyte[15] == 'a'))
                {
                    char[] b = new char[10];
                    for (int i = 0; i < 10; i++)
                    {
                        b[i] = receivebyte[i + 3];
                    }
                    decComPress = decimal.Parse(new string(b));
                    /*decComPress = (decimal)((b[1] - 0x30) * 100 + (b[2] - 0x30) * 10 + (b[4] - 0x30) * 0.1 + (b[5] - 0x30) * 0.01 + (b[6] - 0x30) * 0.001 + (b[7] - 0x30) * 0.0001 + (b[8] - 0x30) * 0.00001 + (b[9] - 0x30) * 0.000001);
                    if (b[0] == '-')
                        decComPress = -decComPress;*/
                }
}
看起来好乱，怎么发成代码！

Answer 3

  private void timeReceive_Tick(object sender, EventArgs e)
  {
     timeReceive.Enabled = false;
  }一触发你就设为FALSE
  public int Receive()能获取一次算好了，有可能一次都获取不到