【求助】关于JSON反序列化

Question

是一个二维数组的JSON报文，第一次接触JSON这方面，新人我已经焦头烂额了。
示例的报文内容如下：
{"total": 6,"rows": [{"id":"314","weatherType":"1.0","weatherName":"qing","maxTemperature":"35.0","minTemperature":"23.0","rainFall":"12.0","snowFall":"12.0"},{"id":"315","weatherType":"2.0","weatherName":"yu","maxTemperature":"40.0","minTemperature":"30.0","rainFall":"0.0","snowFall":"0.0"},{"id":"319","weatherType":"3.0","weatherName":"yin","maxTemperature":"20.0","minTemperature":"10.0","rainFall":"0.0","snowFall":"0.0"},{"id":"379","weatherType":"3.0","weatherName":"yin","maxTemperature":"20.0","minTemperature":"10.0","rainFall":"0.0","snowFall":"0.0"},{"id":"672","weatherType":"3.0","weatherName":"yin","maxTemperature":"20.0","minTemperature":"10.0","rainFall":"0.0","snowFall":"0.0"},{"id":"675","weatherType":"3.0","weatherName":"yin","maxTemperature":"20.0","minTemperature":"10.0","rainFall":"0.0","snowFall":"0.0"}]}
我只能做到将第一层反序列化，但是如何将里面的id等反序列化，新人暂时想不到方法。望各位指教~JSON反序列化

Answer 1

如果你是vs2012，则可以给vs2012 安装一个插件ASP.NET and Web Tools 2012.2安装好这个插件后，就会在web项目出现一个特殊功能“选择性粘贴”将的json字符串直接粘贴为可以被正确序列化对象，有这个对象后，你使用现有了各种json反序列化类都基本可以自动转换过来这玩意的http://blogs.msdn.com/b/webdev/archive/2012/12/18/paste-json-as-classes-in-asp-net-and-web-tools-2012-2-rc.aspxps：当然这是一个简化手段，其实也是一个学习手段，这坛子里这两天很多人都在抱怨着，抱怨那，抱怨微软太自动化了，让他不知道离合器，传动杆是啥子了。我说自动化难道是退步？？你真想知道是啥子，难到就不能自己把发动机盖打开看看？同样这个选择性粘贴是个自动化工具，他能简化你做对应转换对象的时间（别TM抱怨说他自动转换了，你就更弄不清楚json和c#对象到底啥关系了，你自己懒到甚至不愿意看一眼转换后的对象和原始json到底是怎么对应滴，还能怪别人把饭做好了，你都不知道怎么淘米的是把）

Answer 2

class Program
    {
        [DataContract]
        public class t_experience
        {
            [DataMember(Order = 1)]
            public int total { get; set; }
            [DataMember(Order = 2)]
            public Cchild[] rows { get; set; }
        }
        [DataContract]
        public class Cchild
        {
            [DataMember(Order = 1)]
            public int id { get; set; }
            [DataMember(Order = 2)]
            public string weatherType { get; set; }        }
        public static class JSON
        {
            // 反序列化
            public static T parse<T>(string jsonString)
            {
                using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(jsonString)))
                {
                    return (T)new DataContractJsonSerializer(typeof(T)).ReadObject(ms);
                }
            }
            //序列化
            public static string stringify(object jsonObject)
            {
                using (var ms = new MemoryStream())
                {
                    new DataContractJsonSerializer(jsonObject.GetType()).WriteObject(ms, jsonObject);
                    return Encoding.UTF8.GetString(ms.ToArray());
                }
            }
        }        static void Main(string[] args)
        {
            Cchild[] clid = new Cchild[] { new Cchild() { id = 1, weatherType = "weatherType0" }, new Cchild() { id = 2, weatherType = "weatherType1" } };            t_experience p1 = new t_experience() { total = clid.Length, rows = clid };            // 序列化            
            var jsonString = JSON.stringify(new t_experience[] { p1 });
            Console.WriteLine(jsonString);
            var vexperience = JSON.parse<t_experience[]>(jsonString);
            Console.WriteLine("解出第一条第一rows weather值为:{0}", vexperience.First().rows.First().weatherType);
            Console.ReadKey();        }    }
using System.Runtime.Serialization.Json;
using System.Runtime.Serialization;

Answer 3

http://www.soaspx.com/dotnet/asp.net/tech/tech_20120601_9229.html你可以参考参考，希望对你有所帮助 

Answer 4

我记得有专门的json处理库，只是不是官方的，

Answer 5

我把你的数据格式化了下，哪里看出二维数组的存在了？你解释下？
{
total: 6,
rows: 
[
{
"id": "314",
"weatherType": "1.0",
"weatherName": "qing",
"maxTemperature": "35.0",
"minTemperature": "23.0",
"rainFall": "12.0",
"snowFall": "12.0"
},
{
"id": "315",
"weatherType": "2.0",
"weatherName": "yu",
"maxTemperature": "40.0",
"minTemperature": "30.0",
"rainFall": "0.0",
"snowFall": "0.0"
},
{
"id": "319",
"weatherType": "3.0",
"weatherName": "yin",
"maxTemperature": "20.0",
"minTemperature": "10.0",
"rainFall": "0.0",
"snowFall": "0.0"
},
{
"id": "379",
"weatherType": "3.0",
"weatherName": "yin",
"maxTemperature": "20.0",
"minTemperature": "10.0",
"rainFall": "0.0",
"snowFall": "0.0"
},
{
"id": "672",
"weatherType": "3.0",
"weatherName": "yin",
"maxTemperature": "20.0",
"minTemperature": "10.0",
"rainFall": "0.0",
"snowFall": "0.0"
},
{
"id": "675",
"weatherType": "3.0",
"weatherName": "yin",
"maxTemperature": "20.0",
"minTemperature": "10.0",
"rainFall": "0.0",
"snowFall": "0.0"
}
]
}

Answer 6

谢谢这位大大，我一直在纠结怎么绑定rows里面的数据，受指教了。