switch判断

Question

在一个button事件中,根据传入不同的string类型的参数,show不同的窗体出来,因为窗体很多,有没有另外的方法,简化一下switch (e.Tool.Key.ToString())
{
                case "a":
                    a.show();
                    break;
                case "b":
                    b.show();
                    break;
                case "c":
                    ....
}

Answer 1

写个方法不可以么？private void showWindow(一个参数类型, 一个窗体名称)

Answer 2

private void dgv_Data_CellDoubleClick(object sender, DataGridViewCellEventArgs e)
        {
            switch (PageState)
            {
                case WinState.Add://编辑(新增)
                    tspbtn_Modify_Click(sender, e);
                    break;
                case WinState.Modify://编辑
                    tspbtn_Modify_Click(sender, e);
                    break;
                case WinState.Audit://审核
                    tspbtn_Audit_Click(sender, e);
                    break;
                case WinState.Close://关闭
                    tspbtn_Close_Click(sender, e);
                    break;
                case WinState.Browse://列表
                    tspBtn_Detail_Click(sender, e);
                    break;
                default://列表
                    tspBtn_Detail_Click(sender, e);
                    break;
            }
        }这是我的

Answer 3

private void tspBtn_Detail_Click(object sender, EventArgs e)
        {
            try
            {
                if (dgv_Data.SelectedRows.Count > 0)
                {
                    string path = AppDomain.CurrentDomain.BaseDirectory + @"config\receipt\ItemTransApply.xml";
                    FrmItemTranApply frm = new FrmItemTranApply(path);
                    frm.PageState = WinState.Browse;
                    frm.lngItemTransApplyeId = dgv_Data.SelectedRows[0].Cells["flngitemtransapplyid"].Value.ToInt();
                    string fchrAudit = dgv_Data.SelectedRows[0].Cells["fchraudit"].Value.ToStr();
                    if (fchrAudit == "已审核")
                    {
                        frm.lnlVisibleState = 1;
                    }
                    foreach (Form childrenForm in Application.OpenForms) //遍历已经激活的窗体   
                    {
                        if (childrenForm.Name == "frmRetail")  //保证窗体可以前后移动的设置
                        {
                            frm.MdiParent = childrenForm;
                        }                        if (childrenForm is FrmItemTranApply)  //重新激活已经打开的窗体        
                        {
                            childrenForm.Visible = true;
                            childrenForm.Activate();
                            return;
                        }
                    }
                    frm.ParentForm = this;//子父窗体的关联
                    frm.Show();//打开窗体
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show("发生未知错误:" + ex.Message, "美承业务系统", MessageBoxButtons.OK, MessageBoxIcon.Warning);
                return;
            }
        }其中一个窗体

Answer 4

http://www.okhan.net/article/sort021/sort0324/info-3661.htmlhttp://www.cnblogs.com/dcba1112/archive/2011/07/14/2106471.html

Answer 5

告诉你一个比较笨的方法!用一个变量 比如 Dictionary<string,Form> dicForm 把字符串根窗体都存起来 掉的时候 
string fName = e.Tool.Key.ToString();
Form f = dicForm[fname];
f.Show();