XML 解析 ，c#语言？下面这种形式的XML如何解析？求高手？或者类似的代码？

Question

c#xml解析

Answer 1

http://blog.csdn.net/jiankunking/article/details/17992681
http://blog.csdn.net/jiankunking/article/details/17992679
http://blog.csdn.net/jiankunking/article/details/17992683

Answer 2

可以查API 看XML处理的类和方法。网上也有很多的
不过贴个代码 看对你有用不public void analysis(string fileName)
        {
 
            XmlDocument doc = new XmlDocument();
             
            //载入xml
            doc.Load(fileName);
 
            var root = doc.FirstChild;
 
            //当xml文件的根结点名字与定义相匹配才执行
             
            if (root.Name == Root)
            {
                //循环得到结点
                foreach (XmlNode p in root.ChildNodes)
                {
                    foreach (XmlAttribute v in p.Attributes)
                    {
                        var value=v;
                          //做处理
                           .........................                     
                    }
                }
            }
            else
            {
                throw new Exception("配置文件错误");
            }
        }

Answer 3

这个好像之前就有人问过了，一模一样的，是什么接口返回的数据吗？http://blog.csdn.net/chinacsharper/article/details/16824427

Answer 4

        private const string SOAP_XML = "<?xml version=\"1.0\" encoding=\"utf-8\" ?>  " +
            "<SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://www.jiangsuedu.net/justone/\">" +
            "<SOAP-ENV:Header><TransactionID>110000000001</TransactionID><ServiceType>/sms/mt</ServiceType> " + 
            "</SOAP-ENV:Header><SOAP-ENV:Body><GateWayID>YNMC</GateWayID><DstID>15125664368</DstID>" + 
            "<SrcID>099879</SrcID><FeeID>15125664368</FeeID><MsgContent>哈哈</MsgContent>" + 
            "<ServiceID>AYN3913101</ServiceID><MsgID>1234</MsgID><CommitTime>201311130101022</CommitTime>" + 
            "</SOAP-ENV:Body></SOAP-ENV:Envelope> ";
        static void Main(string[] args)
        {
            XmlDocument xmlDocument = new XmlDocument();
            xmlDocument.LoadXml(SOAP_XML);
            XmlElement  item = xmlDocument.DocumentElement;
  
            if (item != null)
            {
                if (item.HasChildNodes)
                {
                     XmlNodeList xmlNodeList = item.ChildNodes;
                     foreach (XmlNode node in xmlNodeList)
                     {
                         printSubItemInfo(node, item.Name);
                     }
                }
                else if (item.NodeType != XmlNodeType.Element)
                    Console.WriteLine("{0}:{1}", item.Name, item.Value);
            }
            Console.Read();
        }
        private static void printSubItemInfo(XmlNode parentNode, string parentName)
        {
            string itemName = string.Format("{0}.{1}", parentName, parentNode.Name);
            if (parentNode.HasChildNodes)
            {
                XmlNodeList xmlNodeList = parentNode.ChildNodes;
                foreach (XmlNode item in xmlNodeList)
                {
                    if (item.HasChildNodes)
                        printSubItemInfo(item, itemName);
                    if (item.NodeType != XmlNodeType.Element)
                        Console.WriteLine("{0}:{1}",  itemName, item.Value);
                }            }
            else if (parentNode.NodeType != XmlNodeType.Element)
                Console.WriteLine("{0}:{1}", itemName, parentNode.Value);
        }

Answer 5

网上有一本书LINQ实战，是中文版的，附带有源码，其中有一章就就LINQtoXML，你看看，他写的很简单