C#.net截取重组字符串

Question

/uplod/dd/images/1234-33-412/5641345641.jpg
改成/uplod/dd/images/1234-33-412/5641345641_small.jpg
和/uplod/dd/images/1234-33-412/s5641345641.jpg
怎么改？

Answer 1

规则就是加后缀 _small和前缀 s  ?

Answer 2

void Main()
{
string str=@"/uplod/dd/images/1234-33-412/5641345641.jpg";
string name=System.IO.Path.GetFileNameWithoutExtension(str);
Console.WriteLine(str.Replace(name,name+"_small"));
Console.WriteLine(str.Replace(name,"s"+name));
/*
/uplod/dd/images/1234-33-412/5641345641_small.jpg
/uplod/dd/images/1234-33-412/s5641345641.jpg 
*/
}

Answer 3

string output = Regex.Replace(input, @"(?i)(?<=/)[^/.]+(?=\.jpg)", "$&_small");
/uplod/dd/images/1234-33-412/5641345641_small.jpgstring output = Regex.Replace(input, @"(?i)(?<=/)[^/.]+(?=\.jpg)", "s$&");
/uplod/dd/images/1234-33-412/s5641345641.jpg

Answer 4

string name=System.IO.Path.GetFileNameWithoutExtension是在做什么呢

Answer 5

获取文件名，也就是5641345641.jpg

Answer 6

string output = Regex.Replace(input, @"(?i)(?<=/)[^/.]+(?=\.)", "$&_small");
/uplod/dd/images/1234-33-412/5641345641_small.jpgstring output = Regex.Replace(input, @"(?i)(?<=/)[^/.]+(?=\.)", "s$&");
/uplod/dd/images/1234-33-412/s5641345641.jpg

Answer 7

实在不行你可以  用 split,这样，你想怎么搞就怎么搞。。