ord可以操作单个字符,如果是字符串,可以用字符数组的型式操作,以下是DELPHI里的一个帮助:uses Dialogs; type Colors = (RED,BLUE,GREEN);var S: string; begin S := 'BLUE has an ordinal value of ' + IntToStr(Ord(BLUE)) + #13#10; S := S + 'The ASCII code for "c" is ' + IntToStr(Ord('c')) + ' decimal'; MessageDlg(S, mtInformation, [mbOk], 0); end;可以这样: var I: Integer; mStr: string; begin for i:=0 to x then Ord(mStr[I])......
呵呵,abcdz+1是不是等于abce呢?
TO: cg1120 你那么做不行啊?还有没有别的方法,我急着呢?TO: westfly(西翔) inc 是一个过程,我怎么使最后一个字符加1后再与原来的字符串连接起来???
procedure TForm1.Button2Click(Sender: TObject); var Len: Integer; sStr: Array [0..255] of char; sTemp : String; iADD : Integer; begin sTemp := 'Hello'; iADD := 10; // Last char add 10; StrCopy(@sStr,Pchar(sTemp)); Len := Length(sTemp); sStr[Len-1] := Chr(Ord(sStr[Len-1]) + iAdd); showmessage(sstr); end;
这样就可以了: var s:string; begin s:='abcd2'; inc(s[length(s)]); showmessage(s); end;
var c : char; c := S[Length(S)]; Inc(Byte(c)); Delete(S,Length(S),1); S := S+c;
type Colors = (RED,BLUE,GREEN);var
S: string;
begin
S := 'BLUE has an ordinal value of ' + IntToStr(Ord(BLUE)) + #13#10;
S := S + 'The ASCII code for "c" is ' + IntToStr(Ord('c')) + ' decimal';
MessageDlg(S, mtInformation, [mbOk], 0);
end;可以这样:
var
I: Integer;
mStr: string;
begin
for i:=0 to x then Ord(mStr[I])......
var
Len: Integer;
sStr: Array [0..255] of char;
sTemp : String;
iADD : Integer;
begin
sTemp := 'Hello';
iADD := 10; // Last char add 10;
StrCopy(@sStr,Pchar(sTemp));
Len := Length(sTemp);
sStr[Len-1] := Chr(Ord(sStr[Len-1]) + iAdd);
showmessage(sstr);
end;
var s:string;
begin
s:='abcd2';
inc(s[length(s)]);
showmessage(s);
end;
c := S[Length(S)];
Inc(Byte(c));
Delete(S,Length(S),1);
S := S+c;