目前想把一个java application写成Windows的系统服务 要用到 Java Service Wrapper 我把整个工程打包成一个jar ，jar里面有好几个main类，Java Service Wrapper wrapper.conf怎么去找到我要用的那个main呢？需要怎么配置？比如我现在工程打包成a.jar 然后 运行里面的com.mx.ui.login这个类怎么在 wrapper.conf配置文件里面配置呢？
# Java Main class. This class must implement the WrapperListener interface
# or guarantee that the WrapperManager class is initialized. Helper
# classes are provided to do this for you. See the Integration section
# of the documentation for details.
wrapper.java.mainclass=login# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=./wrapper.jar
wrapper.java.classpath.2=./a.jar# Java Additional Parameters
wrapper.java.additional.1=
# Java Main class. This class must implement the WrapperListener interface
# or guarantee that the WrapperManager class is initialized. Helper
# classes are provided to do this for you. See the Integration section
# of the documentation for details.
wrapper.java.mainclass=login# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=./wrapper.jar
wrapper.java.classpath.2=./a.jar# Java Additional Parameters
wrapper.java.additional.1=
# or guarantee that the WrapperManager class is initialized. Helper
# classes are provided to do this for you. See the Integration section
# of the documentation for details.
wrapper.java.mainclass=com.mx.ui.login //需要带有包路径即可
# Java Classpath (include wrapper.jar) Add class path elements as
# needed starting from 1
wrapper.java.classpath.1=./wrapper.jar
wrapper.java.classpath.2=./a.jar
# Java Additional Parameters
wrapper.java.additional.1=