在quartz中配置如下job
<calendar class-name="org.quartz.impl.calendar.HolidayCalendar"
replace="true">
<name>holidayCalendar</name>
<description>HolidayCalendar</description>
<base-calendar
class-name="org.quartz.impl.calendar.WeeklyCalendar">
<name>weeklyCalendar</name>
<description>WeeklyCalendar</description>
<base-calendar
class-name="org.quartz.impl.calendar.AnnualCalendar">
<name>annualCalendar</name>
<description>AnnualCalendar</description>
</base-calendar>
</base-calendar>
</calendar>
<job>
<job-detail>
<name>job02</name>
<group>job</group>
<description>定时任务测试</description>
<job-class>com.cncsi.quartz.TestQuartz</job-class>
</job-detail>
<trigger>
<cron>
<name>trigger02</name>
<group>job</group>
<calendar-name>holidayCalendar</calendar-name>
<job-name>job02</job-name>
<job-group>job</job-group>
<cron-expression>0 * * ? * *</cron-expression>
</cron>
</trigger>
</job>不知道如何使用日历,过滤掉具体的日期?
如果要过滤掉具体的日期,如何用配置文件的方式指定?