任意输入数字：假如输入1234 输出 : 壹千贰百叁拾肆元整

Question

我是一位java初学者希望各位前辈指点一下：假如输入1234 输出 : 壹千贰百叁拾肆元整 
网上我查了一下有这种题目可惜没有注释。有些循环体中用的变量不明白
还有如何判断当输入5或者6位数或者更多的时候，输出是拾万或者万希望高位高手能解释一下。最好能有源玛。呵呵谢谢

Answer 1

 public   class   changeToBig   {   
    
        public   changeToBig()   {   
        }   
          
        public   String     hangeToBig(double   value){   
          char[]   hunit={'拾','佰','仟'};                            //段内位置表示   
          char[]   vunit={'万','亿'};                                   //段名表示   
          char[]   digit={'零','壹','贰','叁','肆','伍','陆','柒','捌','玖'};     //数字表示   
          long   midVal   =   (long)(value*100);             //转化成整形   
          String   valStr=String.valueOf(midVal);         //转化成字符串   
    
          String   head=valStr.substring(0,valStr.length()-2);        //取整数部分   
          String   rail=valStr.substring(valStr.length()-2);               //取小数部分   
    
          String   prefix="";                     //整数部分转化的结果   
          String   suffix="";                     //小数部分转化的结果   
          //处理小数点后面的数   
          if(rail.equals("00")){                  //如果小数部分为0   
              suffix="整";   
          }   else{   
              suffix=digit[rail.charAt(0)-'0']+"角"+digit[rail.charAt(1)-'0']+"分";        //否则把角分转化出来   
          }   
          //处理小数点前面的数   
          char[]   chDig=head.toCharArray();                         //把整数部分转化成字符数组   
          char   zero='0';                                                          //标志'0'表示出现过0   
          byte   zeroSerNum   =   0;                                        //连续出现0的次数   
          for(int   i=0;i<chDig.length;i++){                               //循环处理每个数字   
              int   idx=(chDig.length-i-1)%4;                             //取段内位置   
              int   vidx=(chDig.length-i-1)/4;                              //取段位置   
              if(chDig[i]=='0'){                                                    //如果当前字符是0   
                  zeroSerNum++;                                                //连续0次数递增   
                  if(zero   ==   '0'){                                                //标志   
                      zero=digit[0];   
                  }   else   if(idx==0   &&   vidx   >0   &&zeroSerNum   <   4){   
                      prefix   +=   vunit[vidx-1];   
                      zero='0';   
                  }   
                  continue;   
              }   
              zeroSerNum   =   0;                                              //连续0次数清零   
              if(zero   !=   '0')   {                                     //如果标志不为0,则加上,例如万,亿什么的   
                  prefix+=zero;   
                  zero='0';   
              }   
              prefix+=digit[chDig[i]-'0'];                                           //转化该数字表示   
              if(idx   >   0)   prefix   +=   hunit[idx-1];   
              if(idx==0   &&   vidx>0){   
                  prefix+=vunit[vidx-1];                                                //段结束位置应该加上段名如万,亿   
              }   
          }   
    
          if(prefix.length()   >   0)   prefix   +=   '圆';                           //如果整数部分存在,则有圆的字样   
          return   prefix+suffix;                                                            //返回正确表示   
      }   
  public   static   void   main(String   args[]){   
        changeToBig   a=new   changeToBig();   
        System.out.print(a.hangeToBig(876543210000.12));   
  }   
  }   
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