import java.util.*;public class Count { public static void main(String args[]){ int max = 1000; Vector vals = new Vector(); int num = 1234; int count = 0; for(; max>=1; max/=10){ if(num/max>0){ vals.add(new Integer(num/max)); num -= max*(num/max); } }
System.out.println("各位数字分别为:"); int index = 0; while(index < vals.size()){ System.out.print(""+(Integer)vals.elementAt(index++)+"\t"); } } }
import java.util.*;public class Count { public static void main(String args[]){ int max = 1000; Vector vals = new Vector(); int num = 1604; int count = 0;
while(num/max<=0) max /= 10;
while(max>=1){ vals.add(new Integer(num/max)); num -= max*(num/max); max /=10; }
System.out.println("各位数字分别为:"); int index = 0; while(index < vals.size()){ System.out.print(""+(Integer)vals.elementAt(index++)+"\t"); } } }
这个更简单一点:public class Count { public static void main(String args[]){ int num = 120365887; String str = new String(""+num); System.out.println("共有"+str.length()+"位,分别为: "); for(int i=0; i<str.length(); i++){ System.out.print(str.charAt(i)+"\t"); } } }
public class a { public static void main(String [] args) { int i = 234, temp = 1000; while(i/temp == 0) temp /= 10; while(temp!=0) { System.out.println(i/temp); i %= temp; temp /= 10; } } }
import java.util.*;public class tmp{ public static void main(String args[]){ int i=1234; Stack st; if (i==0) System.out.println("it is zero."); else { while (i>0) st.push(i%10); System.out.println(st.size());//输出位数 while (!st.empty()) System.out.print(st.pop()); } } }就我的程序说说以上几位程序的不足之处: 1、字符串做法,如果输入的时候是0012,程序就要出错 2、取余做法,如果这个是就是0,那他也是1位数,而楼上的程序都没有考虑到这一点。
昏,漏了句: while (i>0){ st.push(i%10); i=i/10;//漏掉的 }
String a = String.valueOf(yournumber); System.out.println(a.length); char[] b = a.toCharArray(); for(int i = 0;i<b.size();i++) System.out.println(b[i]);
public static void main(String args[]){
int max = 1000;
Vector vals = new Vector();
int num = 1234;
int count = 0;
for(; max>=1; max/=10){
if(num/max>0){
vals.add(new Integer(num/max));
num -= max*(num/max);
}
}
System.out.println("各位数字分别为:");
int index = 0;
while(index < vals.size()){
System.out.print(""+(Integer)vals.elementAt(index++)+"\t");
}
}
}
public static void main(String args[]){
int max = 1000;
Vector vals = new Vector();
int num = 1604;
int count = 0;
while(num/max<=0)
max /= 10;
while(max>=1){
vals.add(new Integer(num/max));
num -= max*(num/max);
max /=10;
}
System.out.println("各位数字分别为:");
int index = 0;
while(index < vals.size()){
System.out.print(""+(Integer)vals.elementAt(index++)+"\t");
}
}
}
public static void main(String args[]){
int num = 120365887;
String str = new String(""+num);
System.out.println("共有"+str.length()+"位,分别为: ");
for(int i=0; i<str.length(); i++){
System.out.print(str.charAt(i)+"\t");
}
}
}
{
String temp=String.valueOf(num);
System.out.println("位数:");
System.out.println(temp.lenth());
System.out.println("各个数字:");
for(int i=0;i<temp.lemgth();i++)
System.out.print(temp.charAt(i))
System.out.println();
}
public class TT { public static void main(String[] args) {
String s= JOptionPane.showInputDialog("请输入一个数");
for(int j=0;j<s.length();j++)
{
System.out.print(s.charAt(j)+" ");
}
System.out.println();
System.out.println("这是一个"+s.length()+"位数");
}
}
好简单哦!
public class a
{
public static void main(String [] args)
{
int i = 1234, temp = 1000;
while(i%temp == 0)
temp /= 10;
while(temp!=0)
{
System.out.println(i/temp);
i %= temp;
temp /= 10;
}
}
}
while(i/temp == 0) // % -> /
temp /= 10;
public static void main(String [] args) {
int i = 234, temp = 1000;
while(i/temp == 0) temp /= 10;
while(temp!=0) {
System.out.println(i/temp);
i %= temp; temp /= 10;
}
}
}
public static void main(String args[]){
int i=1234;
Stack st;
if (i==0) System.out.println("it is zero.");
else {
while (i>0)
st.push(i%10);
System.out.println(st.size());//输出位数
while (!st.empty())
System.out.print(st.pop());
}
}
}就我的程序说说以上几位程序的不足之处:
1、字符串做法,如果输入的时候是0012,程序就要出错
2、取余做法,如果这个是就是0,那他也是1位数,而楼上的程序都没有考虑到这一点。
while (i>0){
st.push(i%10);
i=i/10;//漏掉的
}
System.out.println(a.length);
char[] b = a.toCharArray();
for(int i = 0;i<b.size();i++)
System.out.println(b[i]);