我的代码如下:运行http//localhost:8080/servlet/ServletAppletComm 时出现了 not inited的错误。import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;import java.awt.*;
import java.applet.*;
import java.awt.event.*;public class ServletAppletComm extends HttpServlet
{
public void doGet(HttpServletRequest request,HttpServletResponse response) 
throws ServletException,IOException
{
response.setContentType("text/html");
PrintWriter out=new PrintWriter(response.getOutputStream());
out.write("<HTML><HEAD><TITLE>HTML Example</TITLE>"+"</HEAD><BODY>");
out.write("<CENTER><B>Servlet"+"通过PARAM标记传递参数给Applet</B>");
out.write("<BR><APPLET code=\"SimpleApplet\""+" width=\"200\"  height=\"200\" >");
//写入PARAM标记
out.write("<param name=\"Date\" value=\"");
out.write(java.text.DateFormat.getDateInstance().format(new java.util.Date()));
out.write("\"></APPLET></CENTER></BODY></HTML>");
out.close();

}
}class SimpleApplet extends Applet
{
Label label1=new Label();

public void init()
{
try
{
jbInit();
}
catch(Exception e)
{
e.printStackTrace();
}
}

public void jbInit() throws Exception
{
this.setSize(200,200);
label1.setText("服务器时间:"+this.getParameter("Date"));
this.add(label1,null);
}

//Get Applet information
public String getApplication()
{
return "读取Servlet传过来的参数!";
}
}在web。xml中的servlet的配置如下:
  <servlet>
        <servlet-name>servCommApp</servlet-name>
        <servlet-class>ServletAppletComm</servlet-class>
    </servlet>
    
<servlet-mapping>
        <servlet-name>servCommApp</servlet-name>
        <url-pattern>/ServletAppletComm/*</url-pattern>
    </servlet-mapping>我想可能是配置的问题,对于servlet调用一个applet的类的情况,产生了两个class文件,而<servlet-class>中只写了个ServletAppletComm,不知道怎么配置啊!!请知道的朋友指点一下!!谢谢