有关JMenuItem接收mouseClicked事件的问题

Question

我定义了一个JMenuItem,
JMenuItem lookMenuItem = new JMenuItem("查看") ;
然后把他添加到JPopupMenu对象中,
JPopupMenu clickTableMenu = new JPopupMenu() ;
clickTableMenu.add(lookMenuItem) ;并给lookMenuItem增加了一个鼠标事件监听器
lookMenuItem.addMouseListener(new MouseListener(){
        public void mouseClicked(MouseEvent e) {
                lookMenuItem_mouseClicked(e) ;}
        public void mousePressed(MouseEvent e) {}
        public void mouseReleased(MouseEvent e) {}
        public void mouseEntered(MouseEvent e){}
        public void mouseExited(MouseEvent e){}
        }) ;但是点击在弹出菜单中点击"查看"JMenuItem时,不执行mouseClicked,但是执行mousePressed和 mouseReleased,不知道是为什么?哪位大侠帮忙解答一下,不胜感激!!!

Answer 1

建议你不要用mouseClicked事件，用actionPerformed事件
lookMenuItem.addActionListener(this);
public void actionPerformed(ActionEvent evt){
    Object source = evt.getSource();
    if (source == lookMenuItem) {
        lookMenuItem_mouseClicked(e)
    }
}

Answer 2

JMenu fileMenu = new JMenu("File");
      JMenuItem openItem = new JMenuItem("Open");
      openItem.addActionListener(new
         ActionListener()
         {
            public void actionPerformed(ActionEvent event)
            {
               openFile();
            }
         });
      fileMenu.add(openItem);      JMenuItem exitItem = new JMenuItem("Exit");
      exitItem.addActionListener(new
         ActionListener()
         {
            public void actionPerformed(ActionEvent event)
            {
               System.exit(0);
            }
         });
      fileMenu.add(exitItem);      JMenuBar menuBar = new JMenuBar();
      menuBar.add(fileMenu);
      setJMenuBar(menuBar);