import java.util.Random;
import java.util.Scanner;
/**
* @author Administrator
*
*/
public class MachineSelection { /**
* @param args
*/
public static void main(String[] args) {
int a = 0;
Random r = new Random();
System.out.println( "请输入36选7机选投注数量:");
Scanner scan = new Scanner(System.in);
int m=scan.nextInt();
for (int j=1; j<=m;j++)
{
System.out.println();
for (int i =1;i <= 7;i++)
{
a=r.nextInt(37)+1;
System.out.print(a+"\t");
}
}
}
}
这些都写好了,就是不知道怎么判断所输出的七位数不重复啊!好像要用数组或者hashset吧!不会用啊!帮帮忙,很急!!!
import java.util.Scanner;
/**
* @author Administrator
*
*/
public class MachineSelection { /**
* @param args
*/
public static void main(String[] args) {
int a = 0;
Random r = new Random();
System.out.println( "请输入36选7机选投注数量:");
Scanner scan = new Scanner(System.in);
int m=scan.nextInt();
for (int j=1; j<=m;j++)
{
System.out.println();
for (int i =1;i <= 7;i++)
{
a=r.nextInt(37)+1;
System.out.print(a+"\t");
}
}
}
}
这些都写好了,就是不知道怎么判断所输出的七位数不重复啊!好像要用数组或者hashset吧!不会用啊!帮帮忙,很急!!!
package random;import java.util.ArrayList;
import java.util.List;public class TestRandom
{
public static void main(String[] args) {
List<Integer> list = new ArrayList<Integer>();
for (int i = 0; i < 7; i++) {
int num = (int) (Math.random()*36+0);
list.add(num);
}
System.out.println(list);
}
}
int num = (int) (Math.random()*37+0);
然后往HashSet里面put
当该set的长度=7时,则为选完PS:楼上的写法生成的7个数该有重复的可能吧
然后往HashSet里面put
当该set的长度=7时,则为选完PS:楼上的写法生成的7个数该有重复的可能吧