Integer.parseInt出錯，爲什麽？

Question

Attention:
"name1" --> "name"
class TestInteger 
{
public static void main(String[] args) throws java.io.IOException
{ System.out.println("Please enter a integer");
String name="";
int c;
while((c=System.in.read())!='\n')
{
name+=(char)c;
} System.out.println("name="+Integer.parseInt(name));
}
}

Answer 1

System.out.println("name="+Integer.parseInt(name.trim()));

Answer 2

把这个程序运行一下看看 我觉得你需要捕获一下异常！！ 
class TestInteger
{
        public static void main(String[] args) throws java.io.IOException
        {
            try{
                System.out.println("Please enter a integer");
                String name="";
                int c;
                while((c=System.in.read())!='\n')
                {
                        name+=(char)c;
                }                System.out.println("name="+Integer.parseInt(name));
            }catch(Exception e){
                System.out.println("input a number please!!");
            }
        }
}

Answer 3

最好用System.out.println("name="+Integer.parseInt(name,10));

Answer 4

binriyue(日月) is right,thank you!