SearchServlet发生错误

Question

SearchServlet发生错误 
问题是不知道如何去跟进 , breakpoint  can't be added
how to debug
bruce says: http://localhost:8080/addressbook/[email protected]&phone=333333656 
type Status report message /addressbook/SearchServlet description The requested resource (/addressbook/SearchServlet) is not available. 代码 
package addressbook.model; import javax.servlet.*; 
import javax.servlet.http.*; 
import java.io.*; 
import java.util.*; class SearchServlet extends HttpServlet  { 
public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException,ServletException{ 
//static{ 
System.out.println("load serverlet class"); 
//} 
String name=request.getParameter("email"); 
        String phone1=request.getParameter("phone"); 
      ........ 编译没有错误 
运行出现开头的提示错误  

Answer 1

路径错误,要看看web.xml是怎么映射的

Answer 2

应该是web.xml的servlet-mapping没配好.贴出来看看.

Answer 3

<?xml version="1.0" encoding="ISO-8859-1"?>
我的SearchServlet.java 文件放的目录为package addressbook.model; 
和jsp不在同一目录 (jsp在webcontent目录) 
web.xml的servlet-mapping  不知道如何配置 
内容如下
<!DOCTYPE web-app PUBLIC 
          "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
          "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd"><web-app>
  <display-name>Struts AddressBook Sample Applications</display-name>
  <servlet>
    <servlet-name>userdatabase</servlet-name>
    <servlet-class>addressbook.UserDatabaseServlet</servlet-class>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>pathname</param-name>
      <param-value>/WEB-INF/userdatabase.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
  </servlet-mapping>
  
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  
  <taglib>
    <taglib-uri>/WEB-INF/app.tld</taglib-uri>
    <taglib-location>/WEB-INF/app.tld</taglib-location>
  </taglib>
  <taglib>
    <taglib-uri>/WEB-INF/struts-bean.tld</taglib-uri>
    <taglib-location>/WEB-INF/struts-bean.tld</taglib-location>
  </taglib>
  <taglib>
    <taglib-uri>/WEB-INF/struts-html.tld</taglib-uri>
    <taglib-location>/WEB-INF/struts-html.tld</taglib-location>
  </taglib>
  <taglib>
    <taglib-uri>/WEB-INF/struts-logic.tld</taglib-uri>
    <taglib-location>/WEB-INF/struts-logic.tld</taglib-location>
  </taglib>
</web-app>

Answer 4

在这行<welcome-file-list>之前添加这么一段试试:
<servlet>
    <servlet-name>search</servlet-name>
    <servlet-class>addressbook.model.SearchServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>search</servlet-name>
    <url-pattern>/addressbook/SearchServlet</url-pattern>
</servlet-mapping> 

Answer 5

还要将SearchServlet.class文件放到
web-inf\classes\addressbook\model下

Answer 6

加了发生错误
The element type "sesrvlet-mapping" must be terminated by the matching end-tag "</sesrvlet-mapping>".<web-app>
  <display-name>Struts AddressBook Sample Applications</display-name>
  <servlet>
    <servlet-name>userdatabase</servlet-name>
    <servlet-class>addressbook.UserDatabaseServlet</servlet-class>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>pathname</param-name>
      <param-value>/WEB-INF/userdatabase.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet>
    
  <servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
      </servlet-mapping>
    <servlet>
    <servlet-name>search</servlet-name>
    <servlet-class>addressbook.model.SearchServlet</servlet-class>
</servlet>
     <sesrvlet-mapping>
        <servlet-name>search</servlet-name>
    <url-pattern>/addressbook/SearchServlet</url-pattern>
  </servlet-mapping>
  

Answer 7

<sesrvlet-mapping>
        <servlet-name>search </servlet-name>
    <url-pattern>/addressbook/SearchServlet </url-pattern>
  </servlet-mapping> 红色的去掉.

Answer 8

配置问题解决, 但是运行发现还是不能找到文件
HTTP Status 404 - /addressbook/SearchServlet--------------------------------------------------------------------------------type Status reportmessage /addressbook/SearchServletdescription The requested resource (/addressbook/SearchServlet) is not available.
--------------------------------------------------------------------------------Apache Tomcat/6.0.18
配置如下 (编译通过)
<web-app>
  <display-name>Struts AddressBook Sample Applications</display-name>
  <servlet>
    <servlet-name>userdatabase</servlet-name>
    <servlet-class>addressbook.UserDatabaseServlet</servlet-class>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>pathname</param-name>
      <param-value>/WEB-INF/userdatabase.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet> <servlet>
       <servlet-name>search</servlet-name>
    <servlet-class>addressbook.model.SearchServlet</servlet-class>
</servlet>
  <servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
      </servlet-mapping>
   
    
 
     <servlet-mapping>
        <servlet-name>search</servlet-name>
    <url-pattern>/addressbook/SearchServlet</url-pattern>
  </servlet-mapping>

Answer 9

 我的调用代码是     
 out.println("<td><a href=SearchServlet?email="+email+"&phone="+phone+">"+ j + "</td>");
          

Answer 10

晕.怎么把这段代码提上来了?
<servlet>
      <servlet-name>search </servlet-name>
    <servlet-class>addressbook.model.SearchServlet </servlet-class>
</servlet> 这个要和对应的<servlet-mapping>放一起的(好像是)你调整好,编译之后,直接打开这个链接试试http://localhost:8080/addressbook/[email protected]&phone=333333656

Answer 11

</servlet> <servlet>
      <servlet-name>search </servlet-name>
    <servlet-class>addressbook.model.SearchServlet </servlet-class>
</servlet>
    <servlet-mapping>
        <servlet-name>search </servlet-name>
    <url-pattern>/addressbook/SearchServlet </url-pattern>
  </servlet-mapping>
编译通不过
提示web.xml有问题， 只能分开放。

Answer 12

能编译通过的是 运行发现还是不能找到文件 
HTTP Status 404 - /addressbook/SearchServlet -------------------------------------------------------------------------------- type Status report message /addressbook/SearchServlet description The requested resource (/addressbook/SearchServlet) is not available.   <servlet>
    <servlet-name>userdatabase</servlet-name>
    <servlet-class>addressbook.UserDatabaseServlet</servlet-class>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>pathname</param-name>
      <param-value>/WEB-INF/userdatabase.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
    <servlet> 
      <servlet-name>SearchServlet </servlet-name> 
    <servlet-class>addressbook.model.SearchServlet </servlet-class> 
</servlet> 
  <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet> 
  
  <servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
      </servlet-mapping>
   
  
         <servlet-mapping>
        <servlet-name>SearchServlet</servlet-name>
    <url-pattern>/addressbook/SearchServlet</url-pattern>
  </servlet-mapping>

Answer 13

你试试把其它servlet和servlet-mapping拿掉,只剩下<servlet>
    <servlet-name>search</servlet-name>
    <servlet-class>addressbook.model.SearchServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>search</servlet-name>
    <url-pattern>/addressbook/SearchServlet</url-pattern>
</servlet-mapping>

Answer 14

不可以 
如果是上面的
第1个登录界面 都找不到 
提示
page can't be found.

Answer 15

你调整好,编译之后,直接打开这个链接试试http://localhost:8080/addressbook/[email protected]&phone=333333656

Answer 16

HTTP Status 404 - /addressbook/SearchServlet--------------------------------------------------------------------------------type Status reportmessage /addressbook/SearchServletdescription The requested resource (/addressbook/SearchServlet) is not available.

Answer 17

晕,不会吧这样都不行
再试试把<servlet-name>中间内容的前后空格去掉吧......

Answer 18

SearchServlet.class放到指定的目录了么?

Answer 19

我的默认是在debug　下，　这个无所谓的
（之前对action　model做的新的java类都是这样执行的　）

Answer 20

在同事热情帮助下 ，奋勇调试最终解决这个问题
－－－感觉提高了很多 至少明白这个servelet是真么回事，不敢说完全明白，但至少有了储备
总结
1 大小写 空格 名称
2 serverlet的class前面要加上public 否则调试不能通过
<servlet>
    <servlet-name>userdatabase </servlet-name>
    <servlet-class>addressbook.UserDatabaseServlet </servlet-class>
    <init-param>
      <param-name>debug </param-name>
      <param-value>2 </param-value>
    </init-param>
    <init-param>
      <param-name>pathname </param-name>
      <param-value>/WEB-INF/userdatabase.xml </param-value>
    </init-param>
    <load-on-startup>1 </load-on-startup>
  </servlet>
    <servlet>
      <servlet-name>search</servlet-name>
    <servlet-class>addressbook.model.SearchServlet</servlet-class>
</servlet>
  <servlet>
    <servlet-name>action </servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet </servlet-class>
    <init-param>
      <param-name>config </param-name>
      <param-value>/WEB-INF/struts-config.xml </param-value>
    </init-param>
    <load-on-startup>2 </load-on-startup>
  </servlet>
 
  <servlet-mapping>
    <servlet-name>action </servlet-name>
    <url-pattern>*.do </url-pattern>
      </servlet-mapping>
 
 
       <servlet-mapping>
        <servlet-name>SearchServlet </servlet-name>
    <url-pattern>SearchServlet</url-pattern>
  </servlet-mapping> 

Answer 21

直言比vc还艰苦 vc不会有真么复杂的配置
vc抛开了繁琐的细节的配置 上手很快
即使mfc也没有搞这么多
语法上java要简单好多（没有指针）