从ORACLE存储过程得到字符串全是"?"的乱码,数字能正常显示,我把这段代码转换成unicode使用如下方法: 测试用:getUnicode("2008-02-28{北京{天津{上海"); public static String toHEXString(byte b) {
return (""+"0123456789abcdef".charAt(0xf&b>>4)+"0123456789abcdef".charAt(b&0xF));
} public static String getUnicode(String setStr) {
String szRet = "";
String szRetTmp = null;
String str = null;
try {
try {
str = new String(setStr.getBytes("gb2312"),"gb2312");
}
catch(Exception ex){
ex.printStackTrace();
}
byte[] bb = str.getBytes("UTF16");
for(int i = 2; i < bb.length; i++)
{
i++;
if(bb[i-1] != 0)
szRetTmp = "\\u" + toHEXString(bb[i-1]) + toHEXString(bb[i]);
else
szRetTmp = new String(bb,i,1,"gb2312");
szRet = szRet + szRetTmp;
}
}catch(Exception ex) {
szRet="Sorry Convert2Unicode method fail!";
ex.printStackTrace();
}
return szRet;
} 得到unicode:2008-02-28{\u5317\u4eac{\u5929\u6d25{\u4e0a\u6d77,然后把这段代码再转换为字符格式,如下方法: unicodeToStr(getUnicode("2008-02-28{北京{天津{上海"));
或
String unicodestr=getUnicode("2008-02-28{北京{天津{上海");
unicodeToStr(unicodestr); public String unicodeToStr(String uStr){
String str = uStr;
System.out.println("str:"+str+" "+str.length());
String[] unicode = str.split("\\\\u");
StringBuffer buf = new StringBuffer(unicode.length - 1);
for(int i = 1; i < unicode.length; i++)
{
buf.append(Integer.parseInt(unicode[i],16));
}
System.out.println(buf.toString());
return str;
} 总是提示错误:
java.lang.NumberFormatException: For input string: "4eac{"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source) 而如果直接使用unicodeToStr("2008-02-28{\u5317\u4eac{\u5929\u6d25{\u4e0a\u6d77");就不会报错,请问该怎么改呀,或者使用其它方法把unicode 转化为字符格式?
谢谢了!
return (""+"0123456789abcdef".charAt(0xf&b>>4)+"0123456789abcdef".charAt(b&0xF));
} public static String getUnicode(String setStr) {
String szRet = "";
String szRetTmp = null;
String str = null;
try {
try {
str = new String(setStr.getBytes("gb2312"),"gb2312");
}
catch(Exception ex){
ex.printStackTrace();
}
byte[] bb = str.getBytes("UTF16");
for(int i = 2; i < bb.length; i++)
{
i++;
if(bb[i-1] != 0)
szRetTmp = "\\u" + toHEXString(bb[i-1]) + toHEXString(bb[i]);
else
szRetTmp = new String(bb,i,1,"gb2312");
szRet = szRet + szRetTmp;
}
}catch(Exception ex) {
szRet="Sorry Convert2Unicode method fail!";
ex.printStackTrace();
}
return szRet;
} 得到unicode:2008-02-28{\u5317\u4eac{\u5929\u6d25{\u4e0a\u6d77,然后把这段代码再转换为字符格式,如下方法: unicodeToStr(getUnicode("2008-02-28{北京{天津{上海"));
或
String unicodestr=getUnicode("2008-02-28{北京{天津{上海");
unicodeToStr(unicodestr); public String unicodeToStr(String uStr){
String str = uStr;
System.out.println("str:"+str+" "+str.length());
String[] unicode = str.split("\\\\u");
StringBuffer buf = new StringBuffer(unicode.length - 1);
for(int i = 1; i < unicode.length; i++)
{
buf.append(Integer.parseInt(unicode[i],16));
}
System.out.println(buf.toString());
return str;
} 总是提示错误:
java.lang.NumberFormatException: For input string: "4eac{"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source) 而如果直接使用unicodeToStr("2008-02-28{\u5317\u4eac{\u5929\u6d25{\u4e0a\u6d77");就不会报错,请问该怎么改呀,或者使用其它方法把unicode 转化为字符格式?
谢谢了!
StringBuffer ret = new StringBuffer();
String tmp = null;
try {
byte[] bb = str.getBytes("UTF-16");
for (int i = 3; i < bb.length; i += 2) {
if (bb[i - 1] != 0)
tmp = toHEXString(bb[i - 1]) + toHEXString(bb[i]);
else
tmp = "00" + toHEXString(bb[i]);
ret.append("\\u").append(tmp);
}
return ret.toString();
} catch (Exception e) {
return str;
}
} public static String unicode2GBK(String str) {
String[] s = str.split("\\\\u");
StringBuffer ret = new StringBuffer();
for (int i = 1; i < s.length; i++) {
ret.append((char) Integer.parseInt(s[i], 16));
}
return ret.toString();
} private static String toHEXString(byte b) {
return ("" + "0123456789ABCDEF".charAt(0xf & b >> 4) + "0123456789ABCDEF"
.charAt(b & 0xF));
}
String temp = gbk2Unicode("2008-02-28{北京{天津{上海");
System.out.println("gbk2Unicode:" + temp);
System.out.println("unicode2GBK:" + unicode2GBK(temp));验证可以通过