{69}
CUSP_CONSUMPTION_SERVICE:array[0..3,0..1] of string=(
{0}('消费服务项ID','CONSUMPTION_SERVICE_ID'),
{1}('消费服务项名称','CONSUMPTION_SERVICE_NAME'),
{2}('消费服务项费用','CONSUMPTION_SERVICE_COST'),
{3}('备注','REMARK')
);
//映射表
Config: array[0..70, 0..1] of string = (
{0}('0', 'SPGZ'),
{1}('1', 'CUSP_MESSAGE_PARA'),
{2}('2', 'CUSP_COMMON_MESSAGE_TYPE'),
{3}('3', 'CUSP_SYSTEM_STATUS'),
{4}('4', 'CUSP_MEMBER'),
{5}('5', 'CUSP_SERVICE_INFOMATION'),
{6}('6', 'CUSP_SERVICE_PACKAGES'),
{7}('7', 'CUSP_VEHICLEBRAND'),
{8}('8', 'CUSP_VEHICLESERIES'),
{9}('9', 'CUSP_VEHICLEMODEL'),能不能直接选取 SPGZ CUSP_MESSAGE_PARA CUSP_COMMON_MESSAGE_TYPE这我写的 呵呵 不行(?='[0-9]+'), {1,}'[a-zA-Z_]+'
CUSP_CONSUMPTION_SERVICE:array[0..3,0..1] of string=(
{0}('消费服务项ID','CONSUMPTION_SERVICE_ID'),
{1}('消费服务项名称','CONSUMPTION_SERVICE_NAME'),
{2}('消费服务项费用','CONSUMPTION_SERVICE_COST'),
{3}('备注','REMARK')
);
//映射表
Config: array[0..70, 0..1] of string = (
{0}('0', 'SPGZ'),
{1}('1', 'CUSP_MESSAGE_PARA'),
{2}('2', 'CUSP_COMMON_MESSAGE_TYPE'),
{3}('3', 'CUSP_SYSTEM_STATUS'),
{4}('4', 'CUSP_MEMBER'),
{5}('5', 'CUSP_SERVICE_INFOMATION'),
{6}('6', 'CUSP_SERVICE_PACKAGES'),
{7}('7', 'CUSP_VEHICLEBRAND'),
{8}('8', 'CUSP_VEHICLESERIES'),
{9}('9', 'CUSP_VEHICLEMODEL'),能不能直接选取 SPGZ CUSP_MESSAGE_PARA CUSP_COMMON_MESSAGE_TYPE这我写的 呵呵 不行(?='[0-9]+'), {1,}'[a-zA-Z_]+'
甘草
等 级:
发表于:2008-02-26 12:54:43 1 楼 得分:
Pascal
===============================
咋了?
一學daonet我就倒一用daonet就輪到它倒下去了
等 级:
发表于:2008-02-26 13:02:32 3 楼 得分:
你
能不能說下要求啊
============================
就是匹配 '0' '1' '2'...后面的字符
{0}('0', 'SPGZ'),
{1}('1', 'CUSP_MESSAGE_PARA'),
{2}('2', 'CUSP_COMMON_MESSAGE_TYPE'),
{3}('3', 'CUSP_SYSTEM_STATUS'),
{4}('4', 'CUSP_MEMBER'),
{5}('5', 'CUSP_SERVICE_INFOMATION'),
{6}('6', 'CUSP_SERVICE_PACKAGES'),
{7}('7', 'CUSP_VEHICLEBRAND'),
{8}('8', 'CUSP_VEHICLESERIES'),
{9}('9', 'CUSP_VEHICLEMODEL'),
甘草
等 级:
发表于:2008-02-26 13:16:535楼 得分:0
{ 0 }这个是注释,别人都不知道我帮你看看
=====================================================
谢谢
import java.util.regex.Pattern;public class Test {
public static void main(String[] args) {
String str = "{69}\n" +
" CUSP_CONSUMPTION_SEVICE:aay[0..3,0..1] of sting=(\n" +
" {0}('消费服务项ID','CONSUMPTION_SEVICE_ID'),\n" +
" {1}('消费服务项名称','CONSUMPTION_SEVICE_NAME'),\n" +
" {2}('消费服务项费用','CONSUMPTION_SEVICE_COST'),\n" +
" {3}('备注','EMAK')\n" +
" );\n" +
" //映射表\n" +
" Config: aay[0..70, 0..1] of sting = (\n" +
" {0}('0', 'SPGZ'),\n" +
" {1}('1', 'CUSP_MESSAGE_PAA'),\n" +
" {2}('2', 'CUSP_COMMON_MESSAGE_TYPE'),\n" +
" {3}('3', 'CUSP_SYSTEM_STATUS'),\n" +
" {4}('4', 'CUSP_MEMBE'),\n" +
" {5}('5', 'CUSP_SEVICE_INFOMATION'),\n" +
" {6}('6', 'CUSP_SEVICE_PACKAGES'),\n" +
" {7}('7', 'CUSP_VEHICLEBAND'),\n" +
" {8}('8', 'CUSP_VEHICLESEIES'),\n" +
" {9}('9', 'CUSP_VEHICLEMODEL'),";
Pattern pattern = Pattern.compile("\\{(\\d)+?\\}\\('\\1',\\s*?'(.+?)'");
Matcher matcher = pattern.matcher(str);
while(matcher.find()) {
System.out.println(matcher.group(1) + " --> " + matcher.group(2));
}
}
}
火龙果
等 级:
发表于:2008-02-26 13:28:539楼 得分:0
怎么又来了啊?
===================
嘿嘿 我这几天在整正则表达式
看到的時候是8樓
點進來的時候是8樓
點進來以后變成9樓了
bao你的手速又變快了啊
apm是不是超過580了??
火龙果
==============
你的方法是匹配
{0}('0', 'SPGZ'
{1}('1', 'CUSP_MESSAGE_PARA'
。。我要的是只想匹配 'SPGZ' 'CUSP_MESSAGE_PARA' 。。
{1}('1', 'CUSP_MESSAGE_PARA'),
火龙果
等 级:
发表于:2008-02-26 13:35:36 16 楼 得分:
什么注释?不是只要红色的部分吗? {0}('0', 'SPGZ'),
{1}('1', 'CUSP_MESSAGE_PARA'),
==============================
是的 我只要红色部分
你应该用StringTable,还是StringMap来做这个事情,我很久不碰PACSAL了。忘记一些类名了
甘草
等 级:
发表于:2008-02-26 13:42:45 18 楼 得分:
楼主的问题,显然不是应该用正则去匹配的,我估计是你跟别人说你想匹配,别人就告诉你正则。
你应该用StringTable,还是StringMap来做这个事情,我很久不碰PACSAL了。忘记一些类名了
=======================================
不是的 是我想通过正则表达式匹配的,这几天自己也在学正则 我也会去试试delphi的 谢谢
火龙果
等 级:
发表于:2008-02-26 14:01:47 21 楼 得分:
你试试看这个,不过向后的零宽度匹配要指定最大值,这里设为了最多10个数字。
=======================
好的 谢谢