解非线性方程之代入法代码如下:public class Report_dainyu {
double x=0.50;
double e=1E-12;
int i=1;
double n_abs,n_cos,n_sa;
/** Creates a new instance of Report_dainyu */
public static void main(String[] args) {
System.out.println("0 0.50");
while(n_abs<e) {
n_cos=cos(double x);//编译时这里提示错误
n_sa=n_cos-x;
n_abs=abs(double n_sa);//编译时这里提示错误
System.out.println(i+" "+n_cos+" "+n_sa);
}
}
}
double x=0.50;
double e=1E-12;
int i=1;
double n_abs,n_cos,n_sa;
/** Creates a new instance of Report_dainyu */
public static void main(String[] args) {
System.out.println("0 0.50");
while(n_abs<e) {
n_cos=cos(double x);//编译时这里提示错误
n_sa=n_cos-x;
n_abs=abs(double n_sa);//编译时这里提示错误
System.out.println(i+" "+n_cos+" "+n_sa);
}
}
}
2,我是个菜鸟.
n_abs=abs(double n_sa);//编译时这里提示错误
都不用加double
n_cos=cos(x); n_abs=abs(n_sa);