js join问题

Question

$(function(){
$("#plugins2>ul>li>ul>li").each(function(index, element){
var fenlei_one = $.trim(this.firstChild.nodeValue); array_fenlei_two = [];
$(this).children().children().each(function(index, element){
if($(element).has('ul')){
var fenlei_third = '';
$(element).children().children().each(function(i,v){
fenlei_third += this.firstChild.nodeValue + '|';

})
fenlei_third = fenlei_third.substr(0,fenlei_third.length -1);
array_fenlei_two.push(fenlei_third.replace(/\s*/g,''));
}
var fenlei_two = this.firstChild.nodeValue.replace(/\s*/g,''); array_fenlei_two.push(fenlei_two); });
//console.log(array_fenlei_two);
console.log(array_fenlei_two.join("@"));
}); })

Answer 1

  array_fenlei_two.push(fenlei_third.replace(/\s*/g,''));这个是什么意思

Answer 2

fenlei_third.replace(/\s*/g,'') 把fenlei_third字符的空格和换行去掉