如何设置弹出窗口的大小和位置，我想把他放在屏幕的中央，大小为横向和纵向屏幕的大小的一半？

Question

window.open('xxx.asp','view','width=500,height=400,top=50,left=100')

Answer 1

在javascript 中取屏幕的横长和纵长，然后取1/2，
该怎么写？
多谢

Answer 2

window.open('xxx.asp','','width='+(screen.width/2)+',height='+(screen.availHeight/2)+',left='+(screen.width/4)+',top='+(screen.availHeight/4)+')

Answer 3

修正一下
window.open('xxx.asp','','width='+(screen.width/2)+',height='+(screen.availHeight/2)+',left='+(screen.width/4)+',top='+(screen.availHeight/4))screen.width    screen.height    屏幕分辨率
screen.avaliWidth screen.availHeight 屏幕可用宽高，主要是去掉任务栏的高度/宽度

Answer 4

function OpenWeb( url, winname, w, h )
{
iT = (screen.availHeight-h)/2-15;
iL = (screen.availWidth-w)/2-3;
window.open(url, winname, "height="+h+",width="+w+",top="+iT+",left="+iL+",toolbar=no,menubar=no,scrollbars=yes,resizable=no,location=no,status=no");
}