拖放问题？？？？？

Question

你要什么反应？我一把鼠标拖离图片就弹出alert

Answer 1

<script>
function beginDrag(elementToDrag,event)  { var delatX=event.clientX-parseInt(elementToDrag.style.left);
var delatY=event.clientY-parseInt(elementToDrag.style.top);
document.attachEvent("onmousemove",moveHandler);
document.attachEvent("onmouseup",upHandler);
pic.attachEvent("onmouseover",overHandler);
event.cancelBubble=true;
event.returnValue=false; function moveHandler(e)  {
if(!e) e=window.event;
elementToDrag.style.left=(e.clientX-delatX)+"px";
elementToDrag.style.top=(e.clientY-delatY)+"px";
e.cancelBubble=true;
} function upHandler(e) {
if(!e) e=window.event;
document.detachEvent("onmouseup",upHandler);
document.detachEvent("onmousemove",moveHandler);
pic.detachEvent("onmouseover",overHandler);
e.cancelBubble=true;
bao.style.left=elementToDrag.style.left;
bao.style.top=elementToDrag.style.top;
    }
}
function overHandler()
{
   alert("warning")
}
</script>
<input type="image" src="csdn.gif" id=bao
style="position:absolute;left:0px;top:0px;z-index:-10"
onmousedown="beginDrag(this,event);">
<br><br><br><br><br><br><br>
<img src="csdn.gif" id="pic">

Answer 2

to:
 wanghr100(灰豆宝宝.net) 
要是我的
<img src="csdn.gif" id="pic">
是在后台动态生成的的呢？

Answer 3

是用ASP生成的话,也一样的啊.

Answer 4

你都没有用上 ondragstart ondragover 事件?? 活用这两个事件, 对你有帮助