<SCRIPT language="javascript">
function getit()
{
theImages=new Image()
theImages.src="logo.jpg"
document.theImage.src=theImages.src
}</SCRIPT> <BODY>
<IMG NAME="theImage" SRC="sb3.jpg" onmouseover="getit()">
</BODY>
给分!!!
function getit()
{
theImages=new Image()
theImages.src="logo.jpg"
document.theImage.src=theImages.src
}</SCRIPT> <BODY>
<IMG NAME="theImage" SRC="sb3.jpg" onmouseover="getit()">
</BODY>
给分!!!
<SCRIPT language="javascript">
theImages=new Image()
theImages.src="images.gif"
function getit()
{
document.theImage.src=theImages.src
}
</SCRIPT>
<BODY>
<a href="javascript:void(null)" onmouseover="getit()"><IMG NAME="theImage" SRC="banner.gif" border=0></a>
</BODY>
</HTML>另外,tongjr(如意) 的办法是不可行的,把图片的下载放到了函数的里面,如果 图片的大和网速慢的话,当鼠标移过去后,并不能看到另外的图片。
to net_lover谢谢以后多象您学习!