jquery 循环取值问题

Question

  $("[name=required].attr('class')=='sel_b'").each(function() {
                requireds += $(this).attr("name");
                requireds += ",";
    });    $("[name=required].attr('class')=='sel_b'") 请问有什么问题? 

Answer 1

写错了 $("[name=required].attr('class')=='sel_b'").each(function() {
  requireds += $(this).attr("id");
  requireds += ",";
  });  不过不与循环条件有关

Answer 2

$("[name='required'][class='sel_b']").each(function () {

Answer 3

$(".sel_b[name='required']").each(function(){
    requireds += $(this).attr("id");
    requireds += ",";
})

Answer 4

$(".sel_b[name='required']").each(function(){
    requireds += $(this).attr("id");
    requireds += ",";
});jquery的类选择器是用点号(.)  用属性选择器的话，有些浏览器是不兼容的...

Answer 5

$(".sel_b[name='required']").each(function(){
    requireds += $(this).attr("id");
    requireds += ",";
});
很方便

Answer 6

http://topic.csdn.net/u/20110818/16/250fd146-7712-4ed1-99a6-a67bd96ebd7b.html?seed=207864214&r=75041884#r_75041884  求解