到第
<select name="select">
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
页
<script language=JavaScript>
function check(){ if(select.value=="1")location="index3.htm"; if(select.value=="2")location="index4.htm"; if(select.value=="3")location="index1.htm"; if(select.value=="4")location="index2.htm"; } </script>
<input type="submit" value="确定"onClick="check()" name="submit" >这个命令怎么只能跳转一次。 跳转第二次时就显示网页无法显示。。怎么回事啊。
<select name="select">
<option value="1" selected>1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
页
<script language=JavaScript>
function check(){ if(select.value=="1")location="index3.htm"; if(select.value=="2")location="index4.htm"; if(select.value=="3")location="index1.htm"; if(select.value=="4")location="index2.htm"; } </script>
<input type="submit" value="确定"onClick="check()" name="submit" >这个命令怎么只能跳转一次。 跳转第二次时就显示网页无法显示。。怎么回事啊。
<input type="button" value="确定"onclick="check()" name="submit" >
当然只跳转一次
所以你应该先看看这个再想想应该怎么说.
http://community.csdn.net/IndexPage/SmartQuestion.aspx
function open(v) {
if (v == "1") {
window.location = "<%=request.getContextPath() %>/index3.html";
}
if (v == "2") {
window.location = "<%=request.getContextPath() %>/index4.html";
}
if (v == "3") {
window.location = "<%=request.getContextPath() %>/index1.html";
}
if (v == "4") {
window.location = "<%=request.getContextPath() %>/index2.html";
}
}
</script><select name="select" onchange="open(this.value)">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>