求一个严格验证身份证号码的函数!!

<SCRIPT Language="JavaScript">
function checkIDCard (str)
{
var isIDCard1 = new Object();
var isIDCard2 = new Object();//身份证正则表达式(15位)
isIDCard1=/^[1-9]\d{7}((0\d)|(1[0-2]))(([0|1|2]\d)|3[0-1])\d{3}$/; //身份证正则表达式(18位) isIDCard2=/^[1-9]\d{5}[1-9]\d{3}((0\d)|(1[0-2]))(([0|1|2]\d)|3[0-1])((\d{4})|\d{3}[A-Z])$/; //验证身份证，如果正确，提交到reg.asp页面
if (isIDCard1.test(str)||isIDCard2.test(str))
{
document.forms["form1"].action = "./reg.asp";
document.forms[0].submit();
return true;
}
alert("请重新输入正确的身份证码！");
return false;}
</SCRIPT>
<Form name="form1" method=post onSubmit="return checkIDCard(this.User_iden.value)">
    <input name="User_iden" id="User_iden" size="18">
    <input type="submit" name="testcall" value="验证身份证号码">
</Form>
/*
==================================================================
功能：验证身份证号码是否有效
提示信息：未输入或输入身份证号不正确！
使用：isIDno(obj,string)
返回：bool
==================================================================
*/
function isIDno(obj,ShowMsg){
var show = IfShow(ShowMsg);

//aCity={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"};
var aCity = "11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91"

var iSum = 0;
var info = "";
var idCardLength = obj.value.length; if(!/^\d{17}(\d|x)$/i.test(obj.value)&&!/^\d{15}$/i.test(obj.value)){
if (show) alert(ShowMsg);
obj.focus();
obj.select();
return false;
} //在后面的运算中x相当于数字10,所以转换成a
obj.value = obj.value.replace(/x$/i,"a");

var curCity = obj.value.substr(0,2); if(!(aCity.indexOf(curCity) >= 0) ){
if (show) alert(ShowMsg);
obj.focus();
obj.select();
return false;
} if (idCardLength==18){
sBirthday=obj.value.substr(6,4)+"-"+Number(obj.value.substr(10,2))+"-"+Number(obj.value.substr(12,2));
var d = new Date(sBirthday.replace(/-/g,"/"))
if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate())){
if (show)
alert(ShowMsg);
obj.focus();
obj.select();
return false;
}
for(var i = 17;i>=0;i--)
iSum += (Math.pow(2,i) % 11) * parseInt(obj.value.charAt(17 - i),11);
if(iSum%11!=1){
if (show)
alert(ShowMsg);
obj.focus();
obj.select();
return false;
} }else if (idCardLength==15){
sBirthday = "19" + obj.value.substr(6,2) + "-" + Number(obj.value.substr(8,2)) + "-" + Number(obj.value.substr(10,2));
var d = new Date(sBirthday.replace(/-/g,"/"))
var dd = d.getFullYear().toString() + "-" + (d.getMonth()+1) + "-" + d.getDate();
if(sBirthday != dd){
if (show)
alert(ShowMsg);
obj.focus();
obj.select();
return false;
}
}
obj.value = obj.value.replace(/a$/i,"x");
return true;
}
<html>
<head>
<title>身份证号是否有效验证</title>
</head>
<body>
请输入身份证号码:
   <input type="text" size="20" id="asidinput" /><input type="button" value="验证" onclick="alert(cidInfo(asidinput.value))" />
<script>
var aCity={
   11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",
   21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",
   33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",
   41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",
   46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",
   54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",
   65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"
   }
function cidInfo(sId){
   var iSum=0
   var info=""
   if(!/^\d{17}(\d|x)$/i.test(sId))
    return false;
   sId=sId.replace(/x$/i,"a");
   if(aCity[parseInt(sId.substr(0,2))]==null)
    return "Error:非法地区";
   sBirthday=sId.substr(6,4)+"-"+Number(sId.substr(10,2))+"-"+Number(sId.substr(12,2));
   var d=new Date(sBirthday.replace(/-/g,"/"))
   if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate()))
    return "Error:非法生日";
   for(var i = 17;i>=0;i --)
    iSum += (Math.pow(2,i) % 11) * parseInt(sId.charAt(17 - i),11)
   if(iSum%11!=1)
    return "Error:非法证号";
   return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女")
}
</script>
</body>
</html>

调试易

求一个严格验证身份证号码的函数!!

解决方案 »