http://topic.csdn.net/u/20090819/17/cb63785d-9ba8-47f7-aea3-57e1e7534226.htmlfunction retrunMapString()
{
if(myAjaxObject.readyState == 4)
{
if(myAjaxObject.status == 200)
{
var returnJSONString = myAjaxObject.responseText;
var returnJSON=JSON.parse(returnJSONString);
var showString="";
alert(returnJSON[0].length);
for(var i in returnJSON[0])
alert("属性为:"+i+"=====>"+"值为:"+returnJSON[0][i])
}
}
}我在这程序中这样做的为什么alert(returnJSON[0].length);
这行出错而你的FOR却正常的循环,请教
{
if(myAjaxObject.readyState == 4)
{
if(myAjaxObject.status == 200)
{
var returnJSONString = myAjaxObject.responseText;
var returnJSON=JSON.parse(returnJSONString);
var showString="";
alert(returnJSON[0].length);
for(var i in returnJSON[0])
alert("属性为:"+i+"=====>"+"值为:"+returnJSON[0][i])
}
}
}我在这程序中这样做的为什么alert(returnJSON[0].length);
这行出错而你的FOR却正常的循环,请教
是for in
便利obj的属性
你要便利的{"1":"高洪岩1","2":"高洪岩2","3":"高洪岩3","4":"高洪岩4","5":"高洪岩5"}
没有length这个属性
for in用法
http://www.w3school.com.cn/js/js_loop_for_in.asp
既然楼主用了JSON.parse那么就应该这么写了
str ='[{"1":"高洪岩1","2":"高洪岩2","3":"高洪岩3","4":"高洪岩4","5":"高洪岩5"}] '
var returnJSON=JSON.parse(str, function(key, value){
alert(key + "==>" + value);
});