求一简单正则表达式

Question

[W|Wo|Wor|Worl|World]
类似这样吧~~

Answer 1

/B(u(s(i(n(e(s(s)?)?)?)?)?)?)?|(W(o(r(l(d)?)?)?)?)?/

Answer 2

<script>
var arr1=["W","Wo","Wor","Worl","World"];
var arr2=["B","Bu","Bus","Busi","Busin","Busine","Busines","Business"];
var re=/^(B(u(s(i(n(e(s(s)?)?)?)?)?)?)?|(W(o(r(l(d)?)?)?)?)?)(?!\w+)/;
for(var i=0;i<arr1.length;i++){
alert(arr1[i]+"===>"+re.test(arr1[i]))
}
for(var i=0;i<arr2.length;i++){
alert(arr2[i]+"===>"+re.test(arr2[i]))
}
alert("wWorld===>"+re.test("sWorld"));
alert("Worldd===>"+re.test("Worldd"));
</script>

Answer 3

很多没明白我的意思，就是用正则实现这样的功能
if (str=="World"||str=="Business")
{}

Answer 4

    <script type="text/javascript">
alert(/^(World|Business)$/.test("World"))
alert(/^(World|Business)$/.test("Business"))
alert(/^(World|Business)$/.test("World Business"))    </script>

Answer 5

/^(World   Business)$/ 
World 与   Business间用\|连接 ， 就是或者的那个符号

Answer 6

World 与   Business间用¦连接

Answer 7

if (str=="World" ¦ ¦str=="Business") 
和
if (str.indexOf("World")！=-1 ¦ ¦str.indexOf("Business")！=-1) 
是不一样的
只能等于World或等于Business，而不是有一个就行。

Answer 8

我的意思不是检索到就行而是一定要等于
比如World为真Worlds为假，
Business为真WorldBusiness为假。

Answer 9

你试过没有,我的就是等于的    
 <script type="text/javascript" >
alert(/^(World|Business)$/.test("World"))   //true
alert(/^(World|Business)$/.test("Business"))   //true
alert(/^(World|Business)$/.test("World Business"))  //false
alert(/^(World|Business)$/.test("Worlds"))   //false
alert(/^(World|Business)$/.test("Businessa"))   //false
     </script >

Answer 10

我晕，除了mingxuan3000，都是火星人

Answer 11

var a=/^(\bWorld\b|\bBusiness\b)$/;
我是这么写的 汗 多此一举了。。