sql for xml 查询求助

Question

sqlxmlquery

Answer 1

--select @x.query('/ArrayOfScheduledTime/ScheduledTime/RecurrenceType')DECLARE @handel int;
EXEC sp_xml_preparedocument @handel output, @x
SELECT * from OPENXML(@handel,'/ArrayOfScheduledTime/ScheduledTime',2)
WITH(RecurrenceType varchar(50)) 
/**************结果*****************
EveryMonday
EveryThursday
EverySunday
*/

Answer 2

你试下
SELECT N.v.value('.' , 'VARCHAR(100)')B FROM @x.nodes('/ArrayOfScheduledTime/ScheduledTime/RecurrenceType')N(v)

Answer 3

declare @x xml
  
select @x='<ArrayOfScheduledTime>
  <ScheduledTime>
    <RecurrenceType>EveryMonday</RecurrenceType>
    <Stamp>
      <dateTime>2000-01-01T19:30:00</dateTime>
    </Stamp>
  </ScheduledTime>
  <ScheduledTime>
    <RecurrenceType>EveryThursday</RecurrenceType>
    <Stamp>
      <dateTime>2000-01-01T19:30:00</dateTime>
    </Stamp>
  </ScheduledTime>
  <ScheduledTime>
    <RecurrenceType>EverySunday</RecurrenceType>
    <Stamp>
      <dateTime>2000-01-01T19:30:00</dateTime>
    </Stamp>
  </ScheduledTime>
</ArrayOfScheduledTime>'select o.value('RecurrenceType[1]','varchar(20)') 'RecurrenceType'
 from (select @x 'x') t
 cross apply x.nodes('/ArrayOfScheduledTime/ScheduledTime') x(o)/*
RecurrenceType
--------------------
EveryMonday
EveryThursday
EverySunday(3 行受影响)
*/