下面是一段excel导出的程序:
private void buttonExcle_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog = new SaveFileDialog();
DfWeb web = new DfWeb(new P101001Service(), this);
P101001DataSet dset = (P101001DataSet)web.Execute("GetDayListBySearch");
_griddata = dset.DayList;
dfDataGridView1.DataSource = _griddata; saveFileDialog.Filter = "Execl files (*.xls)|*.xls"; saveFileDialog.FilterIndex = 0; saveFileDialog.RestoreDirectory = true; saveFileDialog.CreatePrompt = true; saveFileDialog.Title = "Export Excel File To";
if (saveFileDialog.ShowDialog() == DialogResult.Cancel)
{
return;
}
Stream myStream; myStream = saveFileDialog.OpenFile(); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding("gb2312")); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(-0)); string str = "";
try
{
for (int i = 0; i < dfDataGridView1.ColumnCount; i++)
{
if (i > 0)
{ str += "\t"; }
str += dfDataGridView1.Columns[i].HeaderText; }
sw.WriteLine(str); 写内容 for (int j = 0; j < dfDataGridView1.Rows.Count; j++)
{ string tempStr = ""; for (int k = 0; k < dfDataGridView1.Columns.Count; k++)
{
if (k > 0)
{
tempStr += "\t";
}
object value = dfDataGridView1.Rows[j].Cells[k].Value;
if (value == null)
{
value = string.Empty;
}
tempStr += value.ToString(); }
sw.WriteLine(tempStr);
} sw.Close();
myStream.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString()); }
finally
{
sw.Close();
myStream.Close();
}
}
如果gridview导出excel文件时,这个文件名是存在且处于打开状态时怎么处理?如果不处理,程序将会崩溃。
求各位大侠鼎力帮助。
private void buttonExcle_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog = new SaveFileDialog();
DfWeb web = new DfWeb(new P101001Service(), this);
P101001DataSet dset = (P101001DataSet)web.Execute("GetDayListBySearch");
_griddata = dset.DayList;
dfDataGridView1.DataSource = _griddata; saveFileDialog.Filter = "Execl files (*.xls)|*.xls"; saveFileDialog.FilterIndex = 0; saveFileDialog.RestoreDirectory = true; saveFileDialog.CreatePrompt = true; saveFileDialog.Title = "Export Excel File To";
if (saveFileDialog.ShowDialog() == DialogResult.Cancel)
{
return;
}
Stream myStream; myStream = saveFileDialog.OpenFile(); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding("gb2312")); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(-0)); string str = "";
try
{
for (int i = 0; i < dfDataGridView1.ColumnCount; i++)
{
if (i > 0)
{ str += "\t"; }
str += dfDataGridView1.Columns[i].HeaderText; }
sw.WriteLine(str); 写内容 for (int j = 0; j < dfDataGridView1.Rows.Count; j++)
{ string tempStr = ""; for (int k = 0; k < dfDataGridView1.Columns.Count; k++)
{
if (k > 0)
{
tempStr += "\t";
}
object value = dfDataGridView1.Rows[j].Cells[k].Value;
if (value == null)
{
value = string.Empty;
}
tempStr += value.ToString(); }
sw.WriteLine(tempStr);
} sw.Close();
myStream.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString()); }
finally
{
sw.Close();
myStream.Close();
}
}
如果gridview导出excel文件时,这个文件名是存在且处于打开状态时怎么处理?如果不处理,程序将会崩溃。
求各位大侠鼎力帮助。
{
return;
}
Stream myStream; myStream = saveFileDialog.OpenFile(); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding("gb2312")); StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(-0));
写到try里面,捕获异常,然后抛出即可。