使用lag分析函数:select * from(
select item,income,month,income-lag(income,1) over (order by month) as l from
Tab_income order by month) where l<0
select item,income,month,income-lag(income,1) over (order by month) as l from
Tab_income order by month) where l<0
解决方案 »
免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货