表1
备件名 仓库名 数量1 数量2
B1 C1 1 2
B2 C2 1 2
B1 C3 1 2
B3 C1 1 2
B2 C2 1 2
B3 C3 1 2变成表 备件名 仓库C1 仓库C2 仓库C3
B1 -- -- --
B2 -- -- --
B3 -- -- --用一条SQL怎么实现?谢谢
备件名 仓库名 数量1 数量2
B1 C1 1 2
B2 C2 1 2
B1 C3 1 2
B3 C1 1 2
B2 C2 1 2
B3 C3 1 2变成表 备件名 仓库C1 仓库C2 仓库C3
B1 -- -- --
B2 -- -- --
B3 -- -- --用一条SQL怎么实现?谢谢
http://topic.csdn.net/u/20100109/13/6a10c168-f190-4766-b838-adbf03c4ac7b.html?33725
SQL>
SQL> with table1 as (
2 select 'B1' 备件名, 'C1' 仓库名 , 1 数量1 , 2 数量2 from dual union all
3 select 'B2', 'C2' , 1 , 2 from dual union all
4 select 'B1', 'C3' , 1 , 2 from dual union all
5 select 'B3', 'C1' , 1 , 2 from dual union all
6 select 'B2', 'C2' , 1 , 2 from dual union all
7 select 'B3', 'C3' , 1 , 2 from dual
8 )
9 select 备件名,wm_concat(仓库名) 仓库名,sum(数量1) 数量1,sum(数量2) 数量2 from table1 group by 备件名
10 /备件名 仓库名 数量1 数量2
------ -------------------------------------------------------------------------------- ---------- ----------
B1 C1,C3 2 4
B2 C2,C2 2 4
B3 C1,C3 2 4SQL>
备件名 仓库名 数量1 数量2
B1 C1 1 2
B2 C2 1 2
B1 C3 1 2
B3 C1 1 2
B2 C2 1 2
B3 C3 1 2 变成表
备件名 C1 C2 C3
B1 数量1,数量2 数量1,数量2 数量1,数量2
B2 数量1,数量2 数量1,数量2 数量1,数量2
B3 数量1,数量2 数量1,数量2 数量1,数量2实际效果是这样的,但是这个是显示效果,SQL查询出来只要求让备件名全部唯一,仓库名唯一且作为列头就可以了,
你可以去baidu找一下..
(
select 'B1' bname , 'C1' cname , 1 cnt1 , 2 cnt2 from dual
union all
select 'B2' , 'C2' , 1 , 2 from dual
union all
select 'B1' , 'C3' , 1 , 2 from dual
union all
select 'B3' , 'C1' , 1 , 2 from dual
union all
select 'B2', 'C2' , 1 , 2 from dual
union all
select 'B3' , 'C3' , 1 , 2 from dual)
select
bname,
MAX(decode(cname,'C1',CNT,NULL)) AS C1,
MAX(decode(cname,'C2',CNT,NULL)) AS C2,
MAX(decode(cname,'C3',CNT,NULL)) AS C3
FROM
(select bname,cname,cnt1||','||cnt2 as cnt from tt) tt
GROUP BY BNAME
BNAME C1 C2 C3
B1 1,2 1,2
B2 1,2
B3 1,2 1,2
sum(decode(ckm,'c1',sl1,0)) 仓库1,
sum(decode(ckm,'c2',sl1,0)) 仓库2,
sum(decode(ckm,'c3',sl1,0)) 仓库3
from a group by pjm
bname,
MAX(decode(cname,'C1',CNT,NULL)) AS C1,
MAX(decode(cname,'C2',CNT,NULL)) AS C2,
MAX(decode(cname,'C3',CNT,NULL)) AS C3
FROM
(select bname,cname,cnt1||','||cnt2 as cnt from tt) tt
GROUP BY BNAME
这个是什么意思啊,我的仓库是0到N的,备件名也是0到N的!select a.bc_id,a.spc_id,a.sppc_id,a.wi_id,sum(b.ppii_used_amount),sum(b.ppii_amount)
from pare_parts_library_info a,pare_parts_inventory_info b
where a.ppli_id = b.ppli_id group by a.bc_id,a.spc_id,a.sppc_id,a.wi_id
这句是现在的查询语句,查询出的结果类似这样
2 bj148 01 105 0 89
1 bj09 01 105 0 29
1 bj11 01 105 0 5
2 bj144 01 105 0 2
2 bj148 01 106 0 21
1 bj09 01 106 0 1
1 bj09 01 101 0 13
4 bj36 01 105 0 12
2 bj148 01 121 0 3
2 bj148 02 101 0 10效果要求是
105 106 101 121
2 bj148 01 0 89 0 21 0 0 0 3
2 bj148 02
4 bj36 01
1 bj09 01
2 bj144 01
1 bj11 01
-2 bj148 01-(这3个字段统一为备件名) 105(仓库号编号) 0(数量1) 89(数量2)
-1 bj09 01- 105 0 29
3.2
PL/SQL
适用范围:8i,9i,10g及以后版本
这种对于行值不固定的情况可以使用。
下面是我写的一个包,包中
p_rows_column_real用于前述的第一种不限定列的转换;
p_rows_column用于前述的第二种不限定列的转换。
CREATE OR REPLACE PACKAGE pkg_dynamic_rows_column AS
TYPE refc IS REF CURSOR;
PROCEDURE p_print_sql(p_txt VARCHAR2);
FUNCTION f_split_str(p_str VARCHAR2, p_division VARCHAR2, p_seq INT)
RETURN VARCHAR2;
PROCEDURE p_rows_column(p_table IN VARCHAR2,
p_keep_cols IN VARCHAR2,
p_pivot_cols IN VARCHAR2,
p_where IN VARCHAR2 DEFAULT NULL,
p_refc IN OUT refc);
PROCEDURE p_rows_column_real(p_table IN VARCHAR2,
p_keep_cols IN VARCHAR2,
p_pivot_col IN VARCHAR2,
p_pivot_val IN VARCHAR2,
p_where IN VARCHAR2 DEFAULT NULL,
p_refc IN OUT refc);
END;
/
CREATE OR REPLACE PACKAGE BODY pkg_dynamic_rows_column AS
PROCEDURE p_print_sql(p_txt VARCHAR2) IS
v_len INT;
BEGIN
v_len := length(p_txt);
FOR i IN 1 .. v_len / 250 + 1 LOOP
dbms_output.put_line(substrb(p_txt, (i - 1) * 250 + 1, 250));
END LOOP;
END;
FUNCTION f_split_str(p_str VARCHAR2, p_division VARCHAR2, p_seq INT)
RETURN VARCHAR2 IS
v_first INT;
v_last INT;
BEGIN
IF p_seq < 1 THEN
RETURN NULL;
END IF;
IF p_seq = 1 THEN
IF instr(p_str, p_division, 1, p_seq) = 0 THEN
RETURN p_str;
ELSE
RETURN substr(p_str, 1, instr(p_str, p_division, 1) - 1);
END IF;
ELSE
v_first := instr(p_str, p_division, 1, p_seq - 1);
v_last := instr(p_str, p_division, 1, p_seq);
IF (v_last = 0) THEN
IF (v_first > 0) THEN
RETURN substr(p_str, v_first + 1);
ELSE
RETURN NULL;
END IF;
ELSE
RETURN substr(p_str, v_first + 1, v_last - v_first - 1);
END IF;
END IF;
END f_split_str;
PROCEDURE p_rows_column(p_table IN VARCHAR2,
p_keep_cols IN VARCHAR2,
p_pivot_cols IN VARCHAR2,
p_where IN VARCHAR2 DEFAULT NULL,
p_refc IN OUT refc) IS
v_sql VARCHAR2(4000);
TYPE v_keep_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
v_keep v_keep_ind_by;
TYPE v_pivot_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
v_pivot v_pivot_ind_by;
v_keep_cnt INT;
v_pivot_cnt INT;
v_max_cols INT;
v_partition VARCHAR2(4000);
v_partition1 VARCHAR2(4000);
v_partition2 VARCHAR2(4000);
BEGIN
v_keep_cnt := length(p_keep_cols) - length(REPLACE(p_keep_cols, ',')) + 1;
v_pivot_cnt := length(p_pivot_cols) -
length(REPLACE(p_pivot_cols, ',')) + 1;
FOR i IN 1 .. v_keep_cnt LOOP
v_keep(i) := f_split_str(p_keep_cols, ',', i);
END LOOP;
FOR j IN 1 .. v_pivot_cnt LOOP
v_pivot(j) := f_split_str(p_pivot_cols, ',', j);
END LOOP;
v_sql := 'select max(count(*)) from ' || p_table || ' group by ';
FOR i IN 1 .. v_keep.LAST LOOP
v_sql := v_sql || v_keep(i) || ',';
END LOOP;
v_sql := rtrim(v_sql, ',');
EXECUTE IMMEDIATE v_sql
INTO v_max_cols;
v_partition := 'select ';
FOR x IN 1 .. v_keep.COUNT LOOP
v_partition1 := v_partition1 || v_keep(x) || ',';
END LOOP;
FOR y IN 1 .. v_pivot.COUNT LOOP
v_partition2 := v_partition2 || v_pivot(y) || ',';
END LOOP;
v_partition1 := rtrim(v_partition1, ',');
v_partition2 := rtrim(v_partition2, ',');
v_partition := v_partition || v_partition1 || ',' || v_partition2 ||
', row_number() over (partition by ' || v_partition1 ||
' order by ' || v_partition2 || ') rn from ' || p_table;
v_partition := rtrim(v_partition, ',');
v_sql := 'select ';
FOR i IN 1 .. v_keep.COUNT LOOP
v_sql := v_sql || v_keep(i) || ',';
END LOOP;
FOR i IN 1 .. v_max_cols LOOP
FOR j IN 1 .. v_pivot.COUNT LOOP
v_sql := v_sql || ' max(decode(rn,' || i || ',' || v_pivot(j) ||
',null))' || v_pivot(j) || '_' || i || ',';
END LOOP;
END LOOP;
IF p_where IS NOT NULL THEN
v_sql := rtrim(v_sql, ',') || ' from (' || v_partition || ' ' ||
p_where || ') group by ';
ELSE
v_sql := rtrim(v_sql, ',') || ' from (' || v_partition ||
') group by ';
END IF;
FOR i IN 1 .. v_keep.COUNT LOOP
v_sql := v_sql || v_keep(i) || ',';
END LOOP;
v_sql := rtrim(v_sql, ',');
p_print_sql(v_sql);
OPEN p_refc FOR v_sql;
EXCEPTION
WHEN OTHERS THEN
OPEN p_refc FOR
SELECT 'x' FROM dual WHERE 0 = 1;
END;
PROCEDURE p_rows_column_real(p_table IN VARCHAR2,
p_keep_cols IN VARCHAR2,
p_pivot_col IN VARCHAR2,
p_pivot_val IN VARCHAR2,
p_where IN VARCHAR2 DEFAULT NULL,
p_refc IN OUT refc) IS
v_sql VARCHAR2(4000);
TYPE v_keep_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
v_keep v_keep_ind_by;
TYPE v_pivot_ind_by IS TABLE OF VARCHAR2(4000) INDEX BY BINARY_INTEGER;
v_pivot v_pivot_ind_by;
v_keep_cnt INT;
v_group_by VARCHAR2(2000);
BEGIN
v_keep_cnt := length(p_keep_cols) - length(REPLACE(p_keep_cols, ',')) + 1;
FOR i IN 1 .. v_keep_cnt LOOP
v_keep(i) := f_split_str(p_keep_cols, ',', i);
END LOOP;
v_sql := 'select ' || 'cast(' || p_pivot_col ||
' as varchar2(200)) as ' || p_pivot_col || ' from ' || p_table ||
' group by ' || p_pivot_col;
EXECUTE IMMEDIATE v_sql BULK COLLECT
INTO v_pivot;
FOR i IN 1 .. v_keep.COUNT LOOP
v_group_by := v_group_by || v_keep(i) || ',';
END LOOP;
v_group_by := rtrim(v_group_by, ',');
v_sql := 'select ' || v_group_by || ',';
FOR x IN 1 .. v_pivot.COUNT LOOP
v_sql := v_sql || ' max(decode(' || p_pivot_col || ',' || chr(39) ||
v_pivot(x) || chr(39) || ',' || p_pivot_val ||
',null)) as "' || v_pivot(x) || '",';
END LOOP;
v_sql := rtrim(v_sql, ',');
IF p_where IS NOT NULL THEN
v_sql := v_sql || ' from ' || p_table || p_where || ' group by ' ||
v_group_by;
ELSE
v_sql := v_sql || ' from ' || p_table || ' group by ' || v_group_by;
END IF;
p_print_sql(v_sql);
OPEN p_refc FOR v_sql;
EXCEPTION
WHEN OTHERS THEN
OPEN p_refc FOR
SELECT 'x' FROM dual WHERE 0 = 1;
END;
END;
/
本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/you_tube/archive/2009/04/10/4059251.aspx
select 备件名,max(仓库C1) as 仓库C1,max(仓库C2) as 仓库C2,max(仓库C3) as 仓库C3
from
(
select 备件名,convert(varchar,SUM(数量1))+','+convert(varchar,SUM(数量2)) as 仓库C1,null as 仓库C2,null as 仓库C3
from test
where 仓库名='C1'
group by 备件名union allselect 备件名,null as 仓库C1,convert(varchar,SUM(数量1))+','+convert(varchar,SUM(数量2)) as 仓库C2,null as 仓库C3
from test
where 仓库名='C2'
group by 备件名union allselect 备件名,null as 仓库C1,null as 仓库C2,convert(varchar,SUM(数量1))+','+convert(varchar,SUM(数量2)) as 仓库C3
from test
where 仓库名='C3'
group by 备件名
) t
group by 备件名备件名 仓库C1 仓库C2 仓库C3
---------- ------------------------------------------------------------- ------------------------------------------------------------- -------------------------------------------------------------
B1 1,2 1,2 1,2
B2 NULL 1,2 NULL
B3 1,2 NULL 1,2
警告: 聚合或其他 SET 操作消除了 Null 值。(3 行受影响)这是SQL SERVER的语法,你自己转换成ORACLE的语法吧。我这边没有启动ORACLE环境。
insert into test
select 'B1','C1',1,2
union all
select 'B1','C2',1,2
union all
select 'B1','C3',1,2
union all
select 'B3','C1',1,2
union all
select 'B2','C2',1,2
union all
select 'B3','C3',1,2select * from test --drop table test
insert into test
select 'B1','C1',1,2
union all
select 'B1','C2',1,2
union all
select 'B1','C3',1,2
union all
select 'B3','C1',1,2
union all
select 'B2','C2',1,2
union all
select 'B3','C3',1,2select * from test --drop table test