求生成新数组好的办法

Question

RT。如何让2个结构完全一样的数组合并成一个新的数组。用array_merge后面的数组会覆盖前面的。
数组结构为

Answer 1

我猜你是这个意思$a = array('a' => 1);
$b = array('a' => 1);print_r(array_merge_recursive($a, $b));Array
(
    [a] => Array
        (
            [0] => 1
            [1] => 1
        ))

Answer 2

唠叨哥的方法我用过。我数组有7列，结果被分为了7列。
A数组array(
[0] =>
array(['id'] =>
365199916911903
['request_type'] =>
7
['receive_uid'] =>
100004520460114
['type'] =>
2
['obj_id'] =>
50013
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
)
[1] =>
array(['id'] =>
599130963436697
['request_type'] =>
7
['receive_uid'] =>
100004268022279
['type'] =>
2
['obj_id'] =>
50013
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
)
)B数组array(
['id'] =>
409399785810773
['request_type'] =>
7
['receive_uid'] =>
100004251090199
['type'] =>
2
['obj_id'] =>
50013
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
)合并后的C数组array(
[0] =>
array(['id'] =>
365199916911903
['request_type'] =>
7
['receive_uid'] =>
100004520460114
['type'] =>
2
['obj_id'] =>
50013
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
)
[1] =>
array(['id'] =>
409399785810773
['request_type'] =>
7
['receive_uid'] =>
100004251090199
['type'] =>
2
['obj_id'] =>
50013
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
)
)

Answer 3

是还试过 $list[] = array($a,$b);
结果本来平级的数组分为了
array(
0=>array(0=>array,1=>array)
1=>array()
)

Answer 4

$a[] = $b;
$c = $a;
print_r($c);即是你要的C数组

Answer 5

$a = array(
0=>array( 
'id' =>365199916911903,
'request_type'=>7,
'receive_uid' =>100004520460114,
'type' =>2,
'obj_id' =>50013,
'send_uid' =>100004155300493,
'send_time' =>'2013/01/31'
),
1=>array(
'id' =>599130963436697,
'request_type' =>7,
'receive_uid' =>100004268022279,
'type' =>2,
'obj_id' =>50013,
'send_uid' =>100004155300493,
'send_time' =>'2013/01/31'
)
);
$b=array(
'id' =>409399785810773,
'request_type' =>7,
'receive_uid' =>100004251090199,
'type' =>2,
'obj_id' =>50013,
'send_uid' =>100004155300493,
'send_time' =>'2013/01/31'
);
$a[] = $b;
echo "<pre>";
print_r($a);Array
(
    [0] => Array
        (
            [id] => 3.651999169119E+14
            [request_type] => 7
            [receive_uid] => 1.0000452046011E+14
            [type] => 2
            [obj_id] => 50013
            [send_uid] => 1.0000415530049E+14
            [send_time] => 2013/01/31
        )    [1] => Array
        (
            [id] => 5.991309634367E+14
            [request_type] => 7
            [receive_uid] => 1.0000426802228E+14
            [type] => 2
            [obj_id] => 50013
            [send_uid] => 1.0000415530049E+14
            [send_time] => 2013/01/31
        )    [2] => Array
        (
            [id] => 4.0939978581077E+14
            [request_type] => 7
            [receive_uid] => 1.000042510902E+14
            [type] => 2
            [obj_id] => 50013
            [send_uid] => 1.0000415530049E+14
            [send_time] => 2013/01/31
        ))

Answer 6

说明下，a数组是累加的值。一开始没数据的时候，只有a数组，然后传入数组，我当它是b数组，然后新数组等于a数组加上b数组，然后在传入值的时候。依次往a数组后面加，数组的键和结构完全一致

Answer 7

额。简单来说，我先$memcache->get(当天的key);if(不存在这个key)则把传入的任何数组都合并，
数组格式array(
['id'] =>
256676594464467
['request_type'] =>
7
['receive_uid'] =>
100004236761398
['type'] =>
2
['obj_id'] =>
50014
['send_uid'] =>
100004155300493
['send_time'] =>
'2013/01/31'
) 所以说一开始是没有数组的，然后数组按顺序合并起来，因为数组的键都相同，所以无法使用array_merge

Answer 8

搞了半天那你直接把单个的数组赋给一个空的二维数组不就得了 去$b = array('a'=>'1'); 
$a[] = $b;

Answer 9

用array_merge_recursive。。然后
$arr = array();        $count =  count($data['id']);
        for($i=0;$i<$count;$i++){
            $arr[] = array(
                'id'=>$data['id'][$i],
                'request_type'=>$data['request_type'][$i],
                'receive_uid'=>$data['receive_uid'][$i],
                'type'=>$data['type'][$i],
                'obj_id'=>$data['obj_id'][$i],
                'send_uid'=>$data['send_uid'][$i],
                'send_time'=>$data['send_time'][$i],
            );
        }哎。解决~