紧急求救，关于正则表达式的问题

本帖最后由 jxdyzwh 于 2013-03-28 15:35:54 编辑

解决方案 »

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preg_match_all('/<a[^>]+href="?([^>"]+)"?\s*[^>]*>(.+?)<\/a>/i',$data,$arr);
把所有的span内容定义成一个字符串，然后写一个正则表达式匹配，返回一个数组，打印数组，看到结构，根据需要取值：
<?php
$str="<a href='javascript:void(0);'>全部</a><a href='/scenery/scenerysearchlist_6_96__0_0_0.html'>中山</a><a href='/scenery/scenerysearchlist_6_97__0_0_0.html'>珠海</a><a href='/scenery/scenerysearchlist_6_77__0_0_0.html'>潮州</a><a href='/scenery/scenerysearchlist_6_78__0_0_0.html'>东莞</a><a href='/scenery/scenerysearchlist_6_79__0_0_0.html'>佛山</a><a href='/scenery/scenerysearchlist_6_85__0_0_0.html'>茂名</a><a href='/scenery/scenerysearchlist_6_84__0_0_0.html'>揭阳</a><a href='/scenery/scenerysearchlist_6_87__0_0_0.html'>清远</a><a href='/scenery/scenerysearchlist_6_86__0_0_0.html'>梅州</a><a href='/scenery/scenerysearchlist_6_81__0_0_0.html'>河源</a><a href='/scenery/scenerysearchlist_6_80__0_0_0.html'>广州</a><a href='/scenery/scenerysearchlist_6_83__0_0_0.html'>江门</a><a href='/scenery/scenerysearchlist_6_82__0_0_0.html'>惠州</a><a href='/scenery/scenerysearchlist_6_93__0_0_0.html'>云浮</a><a href='/scenery/scenerysearchlist_6_92__0_0_0.html'>阳江</a><a href='/scenery/scenerysearchlist_6_95__0_0_0.html'>肇庆</a><a href='/scenery/scenerysearchlist_6_94__0_0_0.html'>湛江</a><a href='/scenery/scenerysearchlist_6_89__0_0_0.html'>汕尾</a><a href='/scenery/scenerysearchlist_6_88__0_0_0.html'>汕头</a><a href='/scenery/scenerysearchlist_6_91__0_0_0.html'>深圳</a><a href='/scenery/scenerysearchlist_6_90__0_0_0.html'>韶关</a>";
$reg="/\<a\s*href=\'(.*?)\'\>(.*?)\<\/a\>/mi";
preg_match_all($reg,$str,$arr);
echo "<pre>";
print_r($arr);
echo "</pre>";
?>
preg_match_all('/<a[^>]+href=["\']?([^>"\']+)["\']?\s*[^>]*>(.+?)<\/a>/i', $str, $arr, PREG_SET_ORDER);