大神求助

Question

两个二维数组  
    $cart = arrray(array("id"=1,"num="2")); $newcart = arrray(array("id"=1,"num="4");array("id"=2,"num="4"))
怎么样遍历 使它变成   $cart  = arrray(
                                       array("id"=1,"num="6");
                                       array("id"=2,"num="4")) 怎么就拼接它   大神求助啊

Answer 1

$cart = array(array("id"=>1,"num"=>2)); $newcart = array(array("id"=>1,"num"=>4),array("id"=>2,"num"=>4));
 foreach($cart as $v) $t[$v['id']]+=$v['num'];
 
 foreach($newcart as &$v){
         $v['num']+=$t[$v['id']];
 }
print_r($newcart);

Answer 2

不是这样的..... 我的意思是   当传来的数组的id等于原来的id就改变当前数组的数量   如果不等于的话 就把他放在原来的数组中（原来的数组是一个二维的数组） 

Answer 3

两个二维数组  
  $cart = arrray(array("id"=1,"num="2"));（session中的值）  第一次传  $newcart = arrray(array("id"=1,"num="4");array("id"=2,"num="4"))  第二次传  $newcart = arrray(array("id"=9,"num="4");array("id"=1,"num="4"))怎么样遍历 使它变成   $cart  = arrray(
                                      [0]=>array("id"=>1,"num"=>10)
                                      [1]=>array("id"=>2,"num"=>4)
                                      [2]=>array("id"=>9,"num"=>4)
                                     ) 怎么就实现   大神求助啊

Answer 4

两个二维数组  
  $cart = arrray(array("id"=1,"num="2"));（session中的值）  第一次传  $newcart = arrray(array("id"=1,"num="4");array("id"=2,"num="4"))  第二次传  $newcart = arrray(array("id"=9,"num="4");array("id"=1,"num="4"))
  
  第三次传  id 是随时变的.... 
  。。
怎么样遍历 使它变成   $cart  = arrray(
                                      [0]=>array("id"=>1,"num"=>10)
                                      [1]=>array("id"=>2,"num"=>4)
                                      [2]=>array("id"=>9,"num"=>4)
                                     ) 怎么就实现   大神求助啊

Answer 5

一样的道理
$cart =$newcart; 
print_r($cart);