php计算给定时间段内一共有多少周(可以支持跨年计算)

Question

例如：2012-02-04到2012-05-06间隔多少周，周一为一周的起始
跨年也可以支持如2011-12-04到2012-05-06间隔多少周

Answer 1

function computeWeek($date1,$date2){
$diff = strtotime($date2) - strtotime($date1);
$res = ceil($diff/(24*60*60*7));
return $res;
}
echo computeWeek("2011-06-06","2012-06-06")."<br>"; #53
echo computeWeek("2012-06-01","2012-06-07")."<br>"; #1

Answer 2

function computeWeek($date1,$date2){
$diff = strtotime($date2) - strtotime($date1);
$week = floor($diff/(24*60*60*7));
$day = $diff%(24*60*60*7)/(24*60*60);
$res = $week."周又".$day."天";
return $res;
}
echo computeWeek("2011-06-06","2012-06-06")."<br>"; #52周又2天
echo computeWeek("2012-06-01","2012-06-09")."<br>"; #1周又1天

Answer 3

function computeWeek($date1,$date2){
$diff = abs(strtotime($date2) - strtotime($date1)); #取差集的绝对值
$week = floor($diff/(24*60*60*7)); #获取多少周
$day = ($diff%(24*60*60*7))/(24*60*60); #除周数以外的天数
$res = $week."周又".($day+1)."天";
return $res;
}
echo computeWeek("2011-06-06","2012-06-06")."<br>"; #52周又3天
echo computeWeek("2012-06-09","2012-06-01")."<br>"; #1周又2天