php关于请求webservice的问题。请求地址是:http://b2b.ourgame.com/DDService.asmx
如何使用PHP的soap类(nusoap-0.7.3)获取到SaleResponse的结果,我试过用正常的PHP的soap方法去调用这个请求,但是返回的是错误信息。错误信息如下:array (
"faultcode" => "soap:Client",
"faultstring" => "Unexpected wrapper element Sale found.Expected {http://service.web.b2b.lianzhong.com/}Sale."
)请问如何解决?
如何使用PHP的soap类(nusoap-0.7.3)获取到SaleResponse的结果,我试过用正常的PHP的soap方法去调用这个请求,但是返回的是错误信息。错误信息如下:array (
"faultcode" => "soap:Client",
"faultstring" => "Unexpected wrapper element Sale found.Expected {http://service.web.b2b.lianzhong.com/}Sale."
)请问如何解决?
$soapClient = new soapclient($url);/* 读取可用的方法和所需的数据结构 */
print_r( $soapClient->__getFunctions ());
print_r($soapClient->__getTypes () ); $rs = $soapClient->Sale();
print_r($rs);提供的方法
Array
(
[0] => SaleResponse Sale(Sale $parameters)
)
所需参数及类型(使用时将他们组织成关联数组)
Array
(
[0] => struct Sale {
int arg0;
string arg1;
string arg2;
string arg3;
int arg4;
int arg5;
string arg6;
string arg7;
}
[1] => struct SaleResponse {
int return;
}
)
返回的结果
stdClass Object
(
[return] => 200
)
应该差不多吧
ini_set("soap.wsdl_cache_enabled",0);
try{
$client = new SoapClient("http://b2b.ourgame.com/DDService.asmx",array("exceptions" => 1));
var_dump($client->Sale(array("arg0"=>1,"arg1"=>"123","arg2"=>"456","arg3"=>"789","arg4"=>4,"arg5"=>5,"arg6"=>"111","arg7"=>"222")));
}catch(Exception $ex){
var_dump($ex->faultstring);
}服务没有问题啊