<?php
$time = "1152832468";
$newtime = date("Y-m-d",$time);
print $newtime;
?>
<br>
<SCRIPT LANGUAGE="JavaScript">
<!--
var time = <?php echo $time; ?>000;
var d = new Date(time);
document.write(d.getYear()+"/"+(d.getMonth()+1)+"/"+d.getDate());
//-->
</SCRIPT>
$time = "1152832468";
$newtime = date("Y-m-d",$time);
print $newtime;
?>
<br>
<SCRIPT LANGUAGE="JavaScript">
<!--
var time = <?php echo $time; ?>000;
var d = new Date(time);
document.write(d.getYear()+"/"+(d.getMonth()+1)+"/"+d.getDate());
//-->
</SCRIPT>
解决方案 »
- Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
- 大家帮帮忙,求段正则替换语句...有点急。。
- Fatal error: Call to undefined function mysql_connect()
- 大量数据库查询
- 急!谁能给我一份关于oscommerce(电子商务)的源码的中文教程或技术文档。
- 谁知道如何将AEECESS数据库转换成mySQL数据库???
- require和include有什么区别阿?
- 怎样用php实现文件新闻的检索
- 请教阿里云的php,kafka代码示例问题
- php tcpdf writeHTML中文乱码
- php的样板引擎
- [救命]在linux下配置apache2.2 和 php5.1.1问题!!
<!--
var time = "1152832468";
var d = new Date(time*1000);
document.write(d.getFullYear()+"/"+(d.getMonth()+1)+"/"+d.getDate());
//-->
</SCRIPT>