$stmt=$this->_conn->prepare("update ep_tuangou set site_id=4, out_id=1 where id=?");
$stmt->bindParam(1, 4);
$stmt->execute();PHP Fatal error: Cannot pass parameter 2 by reference in D:\usr\www\job\object\core\proPdo.class.php on line 786Fatal error: Cannot pass parameter 2 by reference in D:\usr\www\job\object\core\proPdo.class.php on line 786请问,这是什么情况,哪里写的不对么?
$stmt->bindParam(1, 4);
$stmt->execute();PHP Fatal error: Cannot pass parameter 2 by reference in D:\usr\www\job\object\core\proPdo.class.php on line 786Fatal error: Cannot pass parameter 2 by reference in D:\usr\www\job\object\core\proPdo.class.php on line 786请问,这是什么情况,哪里写的不对么?
PHP的致命错误:无法通过引用传递参数2prepare("update ep_tuangou set site_id=4, out_id=1 where id=?");
你只有一个 ?
为何要产地两个参数呢?
bindParam(1, 4)