求一个PHP redirect的代码。

Question

不可能像jsp那样forward用require目标文件就可以解决了

Answer 1

class gp
{
  var $post;
  var $get;
  function get($post,$get)
  {
    $this->post = $post;
    $this->get = $get;
  }
}
//1.php
<?php
  include("gp.class");
  $obj = new gp($_POST,$_GET);
  include("2.php");
  echo $obj->get["不给看"];
?>
//2.php
<?
  $obj->get["不给看"] ="蛛蛛";
?>

Answer 2

用header("Location:xxx.php");不就行了吗?

Answer 3

我以前贴过这样的函数 function httppost($sURL,$aPostVars,$nMaxReturn=0){
//set_time_limit(100);
$url = parse_url($sURL); if (!$url) return "";
if (!isset($url['port']))  $url['port'] = 80;
if (!isset($url['query'])) $url['query'] = ""; $fp = fsockopen($url['host'], 80); if (!$fp){
return "";
fclose($fp);
exit;
} $postctt="";
if(is_array($aPostVars)){
foreach($aPostVars as $k=>$v){
if($postctt!="") $postctt.="&";
$postctt.=($k."=".urlencode($v));
}
}
$request  = "POST ".$url['path']."?".$url['query']." HTTP/1.1\r\n";
$request .= "Host: ".$url['host']."\r\n";
$request .= "Content-Type: application/x-www-form-urlencoded\r\n";
$request .= "User-Agent: roastduck Http/1.1\r\n";
$request .= "Accept-Language: zh-cn\r\n";
$request .= "Content-length: ".strlen($postctt)."\r\n";
$request .= "Connection: Keep-Alive\r\n\r\n";

$request .= $postctt;
fputs($fp, $request);
$tmp="";
$i=0;
while (!feof ($fp)){
$tmp.= fgetc($fp); 
   $i++;
   if($i>$nMaxReturn && $nMaxReturn>0) break;
} 
fclose($fp);
return $tmp;
}
httppost("http://www.domin.com/page.php?a=1&b=2",array("c"=>3,"d"=>4));

Answer 4

echo "<script>location.href='test.htm';</script>";

Answer 5

http://community.csdn.net/Expert/TopicView1.asp?id=3299669
neo，其实我已经用curl函数作出来了。