php中的ip地址的问题！

Question

$ip为ip地址
<?php
$iparr = explode(".",$ip);
foreach ($iparr as $value)
{
      $newiparr[] = decbin($value); 
}
$newip = implode(".",$newipaddr);
echo $newip;
?>

Answer 1

<?php
$bin_addr = ip2long($ip);
?>

Answer 2

支持： changx(changxing) 的搞法

Answer 3

<?php
    $ip = "202.115.32.24";
$bin_addr = ip2long($ip);
$addr = sprintf("%u", $bin_addr); echo $bin_addr, "<br>", $addr;
?>-898424808
3396542488

Answer 4

<?php
         $ip = "202.115.32.24";
$bin_addr = ip2long($ip);
$addr = sprintf("%u", $bin_addr); echo $bin_addr, "<br>", $addr;
?>Output:-898424808
3396542488

Answer 5

用二进制表示？
<?php
$ip = "202.115.32.24";
printf("%032s", decbin(ip2long($ip)));
?>

Answer 6

$ip = "61.191.72.191";
$tmp = explode(".", $ip);
$tmp[0] = intval($tmp[0]);
$tmp[1] = intval($tmp[1]);
$tmp[2] = intval($tmp[2]);
$tmp[3] = intval($tmp[3]);
$address= $tmp[0] * 256 * 256 *256;
$address+= $tmp[1] * 256 * 256;
$address+= $tmp[2] *256;
$address+= $tmp[3];
echo $address;---
1035946175