给定任意一个时间如：2003-12-15，怎么获得是星期几？？

Question

echo date("l",strtotime("2003-12-15"));

Answer 1

<?
$d = array("星期日","星期一","星期二","星期三","星期四","星期五","星期六");
echo $d[date( "w","2003-11-11" )];
?>

Answer 2

<?
$d = array("日","一","二","三","四","五","六");
echo "星期".$d[date( "w","2003-11-11" )];
?>
这样会不会使用更少内存呢？

Answer 3

对。。<?
$d = array("日","一","二","三","四","五","六");
echo "星期".$d[date( "w","2003-11-11" )];
?>

Answer 4

echo date("l",strtotime("2003-12-15"));这个管用，另外两个不灵呀

Answer 5

晕，不管用不好变通一下嘛？估计是你的php版本太低，date函数不支持直接带"2001-1-1"这样的参数.
<?
$date="2003-11-11";
$d = array("日","一","二","三","四","五","六");
echo "星期".$d[date( "w",strtotime($date) )];
?>